Math Problem Statement

Fiona takes at random three counters from a bag of 8 counters numbered {1, 1, 2, 4, 4, 5, 5, 5}. She adds the numbers on the three counters to get her total. Work out the probability that her total is an odd number.

Solution

Problem Analysis:

The problem involves 8 counters, each marked with specific numbers:

  • Counters: {1, 1, 2, 4, 4, 5, 5, 5}

Fiona randomly selects three counters and calculates their total. We are tasked with finding the probability that the total of these three counters is odd.


Key Idea:

The sum of three numbers is odd if and only if:

  • 1 odd number + 2 even numbers, OR
  • 3 odd numbers.

We analyze these cases step-by-step.


Step 1: Classification of Odd and Even Numbers

From the given counters:

  • Odd Numbers: {1, 1, 5, 5, 5} → 5 odd counters
  • Even Numbers: {2, 4, 4} → 3 even counters

Step 2: Total Possible Combinations

The total number of ways to select 3 counters from 8 is given by the combination formula (nr)\binom{n}{r}, where n=8n = 8 and r=3r = 3:

(83)=876321=56\binom{8}{3} = \frac{8 \cdot 7 \cdot 6}{3 \cdot 2 \cdot 1} = 56

So, there are 56 total combinations.


Step 3: Odd Sum Cases

Case 1: 1 Odd + 2 Even

  • To select 1 odd number from the 5 odd counters: (51)=5\binom{5}{1} = 5
  • To select 2 even numbers from the 3 even counters: (32)=3\binom{3}{2} = 3

The total number of combinations for this case is: (51)(32)=53=15\binom{5}{1} \cdot \binom{3}{2} = 5 \cdot 3 = 15

Case 2: 3 Odd Numbers

  • To select 3 odd numbers from the 5 odd counters: (53)=543321=10\binom{5}{3} = \frac{5 \cdot 4 \cdot 3}{3 \cdot 2 \cdot 1} = 10

The total number of combinations for this case is: 1010


Step 4: Total Favorable Outcomes

Adding the two cases together, the total number of favorable outcomes is: 15+10=2515 + 10 = 25


Step 5: Probability Calculation

The probability is the ratio of favorable outcomes to total outcomes: P(odd sum)=2556P(\text{odd sum}) = \frac{25}{56}


Final Answer:

The probability that Fiona's total is odd is: 2556\boxed{\frac{25}{56}}

Would you like me to break down the steps further or clarify any part? Let me know!


5 Follow-Up Questions:

  1. What is the probability that Fiona’s total is even instead?
  2. How many ways are there to select exactly 2 odd counters and 1 even counter?
  3. Can we generalize this method to any number of counters with any distribution of odd/even numbers?
  4. What would the probability be if we added an extra even counter?
  5. How does the formula for combinations work, and why is it useful?

Tip:

When solving probability problems, always classify outcomes based on conditions (like odd/even) and use the combination formula to simplify counting.

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Math Problem Analysis

Mathematical Concepts

Probability
Combinatorics
Odd and Even Numbers

Formulas

Combination formula: C(n, r) = n! / [r!(n - r)!]

Theorems

Addition of integers to determine odd or even sums

Suitable Grade Level

Grades 9-12