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Let's solve each part based on the given information:

1. **Given**:
   - The probability of having a boy (B) or a girl (G) is equal: \( P(\text{B}) = P(\text{G}) = \frac{1}{2} \).
   - We have three children, which means there are \( 2^3 = 8 \) possible combinations for their genders.

   Possible combinations:
   \[
   \{ \text{BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG} \}
   \]

2. **Calculations**:

   ### a) Probability of All Boys
   - Only one combination has all boys: "BBB".
   - Probability \( = \frac{1}{8} \).

   ### b) Probability of One Girl
   - To have exactly one girl, the combinations are "BBG", "BGB", and "GBB".
   - Probability \( = \frac{3}{8} \).

   ### c) Probability of Two Girls
   - To have exactly two girls, the combinations are "BGG", "GBG", and "GGB".
   - Probability \( = \frac{3}{8} \).

### Summary:
- **a) All boys**: \( \frac{1}{8} \)
- **b) One girl**: \( \frac{3}{8} \)
- **c) Two girls**: \( \frac{3}{8} \)

Would you like further clarification or additional examples? 

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**Related Questions:**
1. What is the probability of having exactly two boys?
2. What is the probability of having no girls?
3. How would the probabilities change if the probability of having a boy was not equal to that of having a girl?
4. Can we use a binomial distribution for this problem? Why or why not?
5. What is the probability of having at least one girl?

**Tip:** When dealing with probabilities of independent events, list all possible outcomes to ensure accuracy in counting favorable cases.

Assume the probability of having a boy is the same as having a girl. What is the probability that a family with three children will have the following?

a) All boys?

b) One girl?

c) Two girls?

Calculate the probabilities for different gender outcomes in a family with three children. This includes finding the probabilities of having all boys, one girl, or two girls. Covers probability and combinatorial concepts suitable for Grades 6-8.

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