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The problem in the image is in Indonesian. Here's a translation:

**Question 7:**
"A married couple wants to have 3 children. The probability that at least one of their children will be a boy is... "

### Solution:
Let’s calculate the probability of getting at least one boy when a couple has 3 children, assuming that each child has an equal chance of being a boy or a girl (i.e., a probability of 0.5 for each).

1. **Total possible outcomes:**
   Each child can either be a boy (B) or a girl (G). So, the total possible combinations of 3 children are:
   \[
   2^3 = 8
   \]
   The possible outcomes are:
   - BBB
   - BBG
   - BGB
   - BGG
   - GBB
   - GBG
   - GGB
   - GGG

2. **Favorable outcomes (at least one boy):**
   The only unfavorable outcome (all girls) is GGG. Therefore, the number of favorable outcomes (at least one boy) is:
   \[
   8 - 1 = 7
   \]

3. **Probability calculation:**
   The probability of having at least one boy is the ratio of favorable outcomes to total outcomes:
   \[
   P(\text{at least one boy}) = \frac{7}{8}
   \]
   Therefore, the probability is:
   \[
   P = 0.875 \text{ or } 87.5\%
   \]

Would you like further details on the solution? Here are some follow-up questions:

### Follow-up Questions:
1. What is the probability of having exactly two boys in this scenario?
2. How would the calculation change if they wanted 4 children instead of 3?
3. How do we calculate the probability of getting all girls?
4. Can you explain the concept of complementary probability using this example?
5. If the probability of having a boy was not 0.5, how would that affect the calculation?

### Tip:
When dealing with probabilities involving "at least one" outcomes, it's often easier to calculate the complement (in this case, "all girls") and subtract that from 1.

Sepasang suami istri menginginkan 3 anak. Peluang anak yang terlahir dari pasangan suami istri tersebut paling sedikitnya satu anak laki-laki adalah ...

Learn how to calculate the probability of having at least one boy in a family with three children. This problem explores the concepts of probability and complementary outcomes, suitable for students in Grades 9-11.

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