Math Problem Statement

A particular telephone number is used to receive both voice calls and fax messages. Suppose that 25% of the incoming calls involve fax messages, and consider a sample of 25 incoming calls. (Round your answers to three decimal places.)

(a) What is the probability that at most 8 of the calls involve a fax message?

(b) What is the probability that exactly 8 of the calls involve a fax message?

(c) What is the probability that at least 8 of the calls involve a fax message?

(d) What is the probability that more than 8 of the calls involve a fax message?

Solution

This problem involves a binomial distribution since each incoming call is either a fax (with probability p=0.25p = 0.25) or not a fax (with probability 1p=0.751 - p = 0.75), and there is a fixed number of trials (n=25n = 25).

Let XX be the number of fax messages among the 25 calls. Then, XX follows a binomial distribution: XBinomial(n=25,p=0.25)X \sim \text{Binomial}(n = 25, p = 0.25)

To solve each part, we use the binomial probability formula or cumulative probabilities, where:

P(X=k)=(nk)pk(1p)nkP(X = k) = \binom{n}{k} p^k (1 - p)^{n - k}

(a) Probability that at most 8 of the calls involve a fax message:

We want to calculate P(X8)P(X \leq 8), which is the cumulative probability from 0 up to 8.

P(X8)=k=08P(X=k)P(X \leq 8) = \sum_{k=0}^{8} P(X = k)

Using binomial cumulative distribution functions (often available on calculators or software):

P(X8)0.819P(X \leq 8) \approx 0.819

(b) Probability that exactly 8 of the calls involve a fax message:

We want P(X=8)P(X = 8), which is calculated using the binomial formula:

P(X=8)=(258)(0.25)8(0.75)170.159P(X = 8) = \binom{25}{8} (0.25)^8 (0.75)^{17} \approx 0.159

(c) Probability that at least 8 of the calls involve a fax message:

This is P(X8)P(X \geq 8), which can be calculated as:

P(X8)=1P(X7)P(X \geq 8) = 1 - P(X \leq 7)

Using cumulative probabilities:

P(X8)10.726=0.274P(X \geq 8) \approx 1 - 0.726 = 0.274

(d) Probability that more than 8 of the calls involve a fax message:

This is P(X>8)P(X > 8), which can be calculated as:

P(X>8)=1P(X8)P(X > 8) = 1 - P(X \leq 8)

Using cumulative probabilities:

P(X>8)10.819=0.181P(X > 8) \approx 1 - 0.819 = 0.181

Summary of Answers:

  1. P(X8)0.819P(X \leq 8) \approx 0.819
  2. P(X=8)0.159P(X = 8) \approx 0.159
  3. P(X8)0.274P(X \geq 8) \approx 0.274
  4. P(X>8)0.181P(X > 8) \approx 0.181

Would you like further explanations on any of these steps or have additional questions?


Here are some related questions you might find helpful:

  1. What is the binomial distribution and when is it applicable?
  2. How can we approximate binomial probabilities using the normal distribution?
  3. What are the mean and variance of a binomial distribution?
  4. How do cumulative distribution functions (CDFs) work for binomial probabilities?
  5. What are other practical applications of the binomial distribution?

Tip: For large values of nn and probabilities not close to 0 or 1, binomial distributions can often be approximated by a normal distribution to simplify calculations.

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Math Problem Analysis

Mathematical Concepts

Statistics
Binomial Distribution
Probability Theory

Formulas

P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)
Cumulative probability: P(X ≤ k) = Σ(P(X = i) for i = 0 to k)

Theorems

Binomial Theorem

Suitable Grade Level

Undergraduate Statistics or AP Statistics