It looks like the image you uploaded contains questions related to the probability of defective LED light bulbs. It seems like you're working with a binomial distribution where the probability of a defective bulb is given as 5% (0.05), and the sample size is 10.

Here are the steps to solve these problems:

1. a. Probability that none of the LED light bulbs are defective: This is asking for $P(X = 0)$, where $X$ is the number of defective light bulbs. We can use the binomial probability formula:

   $P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}$ Where:

   • $n = 10$ (sample size)
   • $k = 0$ (none defective)
   • $p = 0.05$ (probability of a defective bulb)

   Using this formula, we can calculate the probability for $k = 0$.

2. b. Probability that exactly one of the LED light bulbs is defective: This is asking for $P(X = 1)$. You would use the same binomial formula with $k = 1$.

3. c. Probability that three or fewer of the LED light bulbs are defective: This asks for $P(X \leq 3)$. This can be calculated by adding up the probabilities from $P(X = 0)$ to $P(X = 3)$.

4. d. Probability that four or more of the LED light bulbs are defective: This asks for $P(X \geq 4)$. To find this, you can use the complement rule: $P(X \geq 4) = 1 - P(X \leq 3)$

I see that the probabilities for each part have already been provided in the image:

• a. 0.5987
• b. 0.3151
• c. 0.9989
• d. 0.0116

Would you like me to explain how these values were obtained, or do you need help with any specific part of the process?