Math Problem Statement

Use the contingency table below to find the probability of the following events: a. A|B, b. A|B', c. A'|B', d. Are events A and B independent?

Solution

To answer the probability questions using the contingency table, let me break down the data.

From the table:

  • A ∩ B (both A and B happen) = 20
  • A ∩ B' (A happens and B does not) = 30
  • A' ∩ B (A does not happen and B does) = 30
  • A' ∩ B' (neither A nor B happens) = 50

Now, let's calculate the probabilities:

Total number of outcomes:

Total=20+30+30+50=130\text{Total} = 20 + 30 + 30 + 50 = 130

a. P(AB)P(A | B) (Probability of A given B)

The conditional probability formula is: P(AB)=P(AB)P(B)P(A | B) = \frac{P(A \cap B)}{P(B)}

  • P(AB)=20130P(A \cap B) = \frac{20}{130}
  • P(B)=20+30130=50130P(B) = \frac{20 + 30}{130} = \frac{50}{130}

P(AB)=2013050130=2050=0.4P(A | B) = \frac{\frac{20}{130}}{\frac{50}{130}} = \frac{20}{50} = 0.4

b. P(AB)P(A | B') (Probability of A given B')

P(AB)=P(AB)P(B)P(A | B') = \frac{P(A \cap B')}{P(B')}

  • P(AB)=30130P(A \cap B') = \frac{30}{130}
  • P(B)=30+50130=80130P(B') = \frac{30 + 50}{130} = \frac{80}{130}

P(AB)=3013080130=3080=0.375P(A | B') = \frac{\frac{30}{130}}{\frac{80}{130}} = \frac{30}{80} = 0.375

c. P(AB)P(A' | B') (Probability of A' given B')

P(AB)=P(AB)P(B)P(A' | B') = \frac{P(A' \cap B')}{P(B')}

  • P(AB)=50130P(A' \cap B') = \frac{50}{130}

P(AB)=5013080130=5080=0.625P(A' | B') = \frac{\frac{50}{130}}{\frac{80}{130}} = \frac{50}{80} = 0.625

d. Are events A and B independent?

To check for independence, we verify if: P(AB)=P(A)×P(B)P(A \cap B) = P(A) \times P(B)

  • P(AB)=20130=0.1538P(A \cap B) = \frac{20}{130} = 0.1538
  • P(A)=20+30130=50130=0.3846P(A) = \frac{20 + 30}{130} = \frac{50}{130} = 0.3846
  • P(B)=20+30130=50130=0.3846P(B) = \frac{20 + 30}{130} = \frac{50}{130} = 0.3846

Now, check if P(AB)=P(A)×P(B)P(A \cap B) = P(A) \times P(B): P(A)×P(B)=0.3846×0.3846=0.1478P(A) \times P(B) = 0.3846 \times 0.3846 = 0.1478 Since 0.15380.14780.1538 \neq 0.1478, A and B are not independent.


Would you like more details on any step, or do you have any questions?

Here are 5 related questions you could explore:

  1. How do we calculate the joint probability of A and B?
  2. What is the general condition for two events to be independent?
  3. How would the table change if A and B were independent?
  4. Can you explain the concept of conditional probability in more detail?
  5. What happens if all probabilities in a contingency table are equal?

Tip: When dealing with conditional probabilities, always check if you need the total probability of the condition (denominator) to be sure you're calculating correctly.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Conditional Probability
Independence of Events
Contingency Table

Formulas

P(A | B) = P(A ∩ B) / P(B)
P(A | B') = P(A ∩ B') / P(B')
P(A' | B') = P(A' ∩ B') / P(B')
P(A ∩ B) = P(A) × P(B) for independent events

Theorems

Conditional Probability Theorem
Independence Criterion

Suitable Grade Level

Grades 10-12