Math Problem Statement

The final exam grade of a statistics class has a skewed distribution with mean of 79 and standard deviation of 8.2. If a random sample of 35 students selected from this class, then what is the probability that average final exam grade of this sample is between 76 and 82? Answer: (round to 4 decimal places)

Solution

To solve this problem, we need to calculate the probability that the average final exam grade of a sample of 35 students lies between 76 and 82. We are given the following information:

  • Mean of the population (μ\mu) = 79
  • Standard deviation of the population (σ\sigma) = 8.2
  • Sample size (nn) = 35

Step 1: Calculate the standard error (SE)

The standard error (SE) of the sample mean is calculated using the formula:

SE=σnSE = \frac{\sigma}{\sqrt{n}}

Substituting the values:

SE=8.2358.25.9161.386SE = \frac{8.2}{\sqrt{35}} \approx \frac{8.2}{5.916} \approx 1.386

Step 2: Convert the problem to a standard normal distribution (Z-scores)

Now, we need to convert the range 76 to 82 to Z-scores. The formula to compute a Z-score is:

Z=XμSEZ = \frac{X - \mu}{SE}

For X=76X = 76:

Z1=76791.38631.3862.17Z_1 = \frac{76 - 79}{1.386} \approx \frac{-3}{1.386} \approx -2.17

For X=82X = 82:

Z2=82791.38631.3862.17Z_2 = \frac{82 - 79}{1.386} \approx \frac{3}{1.386} \approx 2.17

Step 3: Find the probabilities corresponding to these Z-scores

Using a Z-table or a standard normal distribution calculator:

  • The probability of Z=2.17Z = -2.17 is approximately P(Z<2.17)0.0150P(Z < -2.17) \approx 0.0150.
  • The probability of Z=2.17Z = 2.17 is approximately P(Z<2.17)0.9850P(Z < 2.17) \approx 0.9850.

Step 4: Calculate the probability between the two Z-scores

The probability that the sample mean is between 76 and 82 is the difference between these two probabilities:

P(76Xˉ82)=P(Z<2.17)P(Z<2.17)P(76 \leq \bar{X} \leq 82) = P(Z < 2.17) - P(Z < -2.17)

P(76Xˉ82)=0.98500.0150=0.9700P(76 \leq \bar{X} \leq 82) = 0.9850 - 0.0150 = 0.9700

Final Answer:

The probability that the average final exam grade of the sample is between 76 and 82 is approximately 0.9700.


Would you like more details on how we calculated this, or do you have any questions? Here are some follow-up questions that could expand on this topic:

  1. How does the sample size nn affect the standard error and, consequently, the probability?
  2. What happens to the probability if the sample size were increased to 50?
  3. What is the impact of a larger population standard deviation on the Z-scores?
  4. How would the result change if the distribution of the population was normal instead of skewed?
  5. What is the difference between population parameters and sample statistics in hypothesis testing?

Tip: As sample sizes increase, the sampling distribution of the sample mean tends to approximate a normal distribution more closely due to the Central Limit Theorem, even if the population distribution is skewed.

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Math Problem Analysis

Mathematical Concepts

Statistics
Probability
Z-scores
Standard Error
Normal Distribution

Formulas

Standard Error (SE) = σ / √n
Z = (X - μ) / SE

Theorems

Central Limit Theorem

Suitable Grade Level

Grades 11-12