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The problem asks for the probability that an athlete is either a football player or a basketball player, given the following information:

- 51% of athletes are football players.
- 18% of athletes are basketball players.
- 17% of athletes play both football and basketball.

This is a typical problem involving the probability of the union of two events, where you are given:

- \( P(\text{Football}) = 0.51 \)
- \( P(\text{Basketball}) = 0.18 \)
- \( P(\text{Football} \cap \text{Basketball}) = 0.17 \)

To find the probability that an athlete is either a football player or a basketball player (i.e., \( P(\text{Football} \cup \text{Basketball}) \)), we can use the formula:

\[
P(\text{Football} \cup \text{Basketball}) = P(\text{Football}) + P(\text{Basketball}) - P(\text{Football} \cap \text{Basketball})
\]

Substituting the given values:

\[
P(\text{Football} \cup \text{Basketball}) = 0.51 + 0.18 - 0.17 = 0.52
\]

Therefore, the probability that an athlete is either a football player or a basketball player is **0.52**, or **52%**.

Would you like more details on this solution, or do you have any other questions?

Here are some related questions you might find useful:
1. How would the probability change if no athlete played both sports?
2. How do you calculate the probability of exclusive events?
3. What is the formula for conditional probability in such problems?
4. Can you visualize this problem using a Venn diagram?
5. How would you calculate the probability if the events were dependent?

**Tip:** Always remember to subtract the intersection in such problems to avoid counting the overlap twice.

A survey of athletes at a high school is conducted, and the following facts are discovered: 51% of the athletes are football players, 18% are basketball players, and 17% of the athletes play both football and basketball. An athlete is chosen at random from the high school: what is the probability that the athlete is either a football player or a basketball player?

Calculate the probability that an athlete is either a football or basketball player, using the addition rule of probability. Given 51% of athletes play football, 18% play basketball, and 17% play both, the final probability is 52%. Suitable for students in Grades 10-12.

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