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The problem asks for the probability that an athlete is either a football player or a basketball player, given certain percentages:

- 55% of athletes are football players.
- 42% of athletes are basketball players.
- 30% of athletes play both football and basketball.

We can solve this using the formula for the union of two events:

\[
P(\text{Football or Basketball}) = P(\text{Football}) + P(\text{Basketball}) - P(\text{Both})
\]

Where:
- \( P(\text{Football}) = 55\% \),
- \( P(\text{Basketball}) = 42\% \),
- \( P(\text{Both}) = 30\% \).

Now, let's calculate the probability:

\[
P(\text{Football or Basketball}) = 55\% + 42\% - 30\% = 67\%
\]

Thus, the probability that an athlete is either a football player or a basketball player is **67%**.

Would you like more details on how this was calculated or have any further questions?

Here are 5 related questions to consider:
1. What is the probability that an athlete is only a football player?
2. What is the probability that an athlete is only a basketball player?
3. How do we calculate the probability that an athlete plays neither sport?
4. Can you find the percentage of athletes who do not play basketball?
5. How does this formula generalize to more than two events?

**Tip:** When solving problems involving the union of two or more events, always remember to subtract the overlap (intersection) to avoid double-counting.

A survey of athletes at a high school is conducted, and the following facts are discovered: 55% of the athletes are football players, 42% are basketball players, and 30% of the athletes play both football and basketball. An athlete is chosen at random from the high school: what is the probability that the athlete is either a football player or a basketball player?

Learn how to calculate the probability that an athlete plays either football or basketball, using percentages and the inclusion-exclusion principle. This problem explores key probability concepts and is suitable for Grades 9-11 students.

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