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We are given the following problem:

- 10% of all drivers receive a speeding ticket each year.
- We need to find the probability that all 4 drivers selected at random will get a speeding ticket.

### Solution:

The probability that a single driver gets a speeding ticket is \( p = 0.10 \), and the probability that all 4 drivers get speeding tickets can be modeled as the product of independent events.

The probability of all 4 drivers getting a ticket is:
\[
P(\text{all 4 drivers get a ticket}) = (0.10)^4 = 0.0001
\]

Thus, the correct answer is **0.0001**.

Would you like a more detailed explanation or have any questions?

Here are 5 related questions to consider:
1. What is the probability that none of the 4 drivers get a speeding ticket?
2. How do we calculate the probability that exactly 2 out of 4 drivers get a speeding ticket?
3. What is the probability that at least one of the 4 drivers gets a speeding ticket?
4. How would the result change if the probability of getting a speeding ticket was 20% instead of 10%?
5. How can the binomial probability formula be used for such problems?

**Tip:** For problems involving independent events, the total probability is the product of the probabilities of each individual event occurring.

It is known that 10% of all drivers get a speeding ticket each year. If we select 4 drivers at random, what is the probability that all 4 drivers get a speeding ticket?

Learn how to calculate the probability that all 4 drivers receive a speeding ticket given that 10% of drivers get a ticket each year. This problem uses key probability concepts, including the multiplication rule for independent events. Suitable for students in Grades 9-12.

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