The question in the image is in Indonesian and translates to:

"How many prime factors are present in the number $(30)^3$?"

Solution:

First, break down the number $30$ into its prime factors:

$30 = 2 \times 3 \times 5$

Now, raise this to the power of 3:

$(30)^3 = (2 \times 3 \times 5)^3 = 2^3 \times 3^3 \times 5^3$

The prime factors of $(30)^3$ are $2$, $3$, and $5$. Each prime factor appears with an exponent, but the question asks for the number of distinct prime factors. There are 3 distinct prime factors: $2$, $3$, and $5$.

Answer:

The correct answer is 3.

Would you like further details or have any questions?

Here are 5 related questions to expand your understanding:

1. How do you find the prime factors of any number?
2. What are the properties of prime numbers?
3. How does exponentiation affect the prime factorization of a number?
4. Can a composite number have more than one distinct prime factor?
5. How would the prime factorization change if you raised $30$ to a higher power, such as $30^5$?

Tip: Always break down a number into its prime factors before applying exponentiation in problems involving prime factorizations.