Describe the preparation of 500mL M Cl solution from solid BaCl2.2H2O (244 g/mol)

To prepare 500 mL of a 1 M BaCl₂·2H₂O (Barium Chloride Dihydrate) solution, follow these steps:

### Materials Required:
- **BaCl₂·2H₂O** (Barium Chloride Dihydrate)
- Distilled water
- A balance (to measure mass)
- A 500 mL volumetric flask or graduated cylinder
- A stirring rod or magnetic stirrer

### Procedure:

1. **Calculate the Mass of BaCl₂·2H₂O Required**:
   - **Molarity (M)** = 1 M
   - **Volume (V)** = 500 mL = 0.5 L
   - **Molar mass of BaCl₂·2H₂O** = 244 g/mol
   - **Mass (m)** = Molarity (M) × Volume (V) × Molar Mass (Mᵣ)
   \[
   m = 1 \, \text{M} \times 0.5 \, \text{L} \times 244 \, \text{g/mol} = 122 \, \text{g}
   \]
   You will need 122 g of BaCl₂·2H₂O.

2. **Weigh the Solid**:
   - Using a balance, accurately weigh 122 g of BaCl₂·2H₂O.

3. **Dissolve the BaCl₂·2H₂O in Water**:
   - Transfer the weighed BaCl₂·2H₂O into a 500 mL volumetric flask.
   - Add distilled water gradually to the flask while gently stirring to help dissolve the solid.

4. **Make up to the Mark**:
   - Once the solid is fully dissolved, continue to add distilled water until the solution reaches the 500 mL mark on the volumetric flask.

5. **Mix the Solution**:
   - Cap the flask and invert it several times or stir well to ensure the solution is homogeneous.

Your 500 mL of 1 M BaCl₂·2H₂O solution is now ready for use.

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### Related Questions:
1. How would you prepare a 0.5 M solution of BaCl₂·2H₂O instead?
2. What safety precautions should you take while handling BaCl₂·2H₂O?
3. How does the presence of water of hydration (H₂O) in BaCl₂·2H₂O affect the molar mass?
4

Learn how to prepare a 500mL 1 M BaCl₂·2H₂O solution from solid BaCl₂·2H₂O. Detailed step-by-step instructions including calculations of molarity, mass of solute required, and solution preparation techniques. Suitable for advanced high school and college chemistry students.

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