2. What is the molarity of a solution that was prepared by dissolving 82.0 g of CaCl2
(molar mass = 111.1 g/mol) in enough water to make 812 mL of solution?

To calculate the molarity (M) of a solution, we use the formula:

\[
M = \frac{{\text{{moles of solute}}}}{{\text{{volume of solution in liters}}}}
\]

### Step 1: Calculate moles of \( \text{CaCl}_2 \)
To find the moles of calcium chloride (\( \text{CaCl}_2 \)), use its molar mass:

\[
\text{{moles}} = \frac{{\text{{mass}}}}{{\text{{molar mass}}}}
\]

Given:
- Mass of \( \text{CaCl}_2 \) = 82.0 g
- Molar mass of \( \text{CaCl}_2 \) = 111.1 g/mol

\[
\text{{moles of }} \text{CaCl}_2 = \frac{{82.0 \, \text{g}}}{{111.1 \, \text{g/mol}}}
\]

\[
\text{{moles of }} \text{CaCl}_2 = 0.738 \, \text{mol}
\]

### Step 2: Convert volume to liters
The volume of the solution is given as 812 mL. To convert this to liters:

\[
\text{{volume in liters}} = \frac{{812 \, \text{mL}}}{{1000}} = 0.812 \, \text{L}
\]

### Step 3: Calculate the molarity
Now, use the moles of solute and the volume of the solution in liters to find the molarity:

\[
M = \frac{{0.738 \, \text{mol}}}{{0.812 \, \text{L}}}
\]

\[
M \approx 0.909 \, \text{M}
\]

### Final Answer:
The molarity of the solution is approximately **0.909 M**.

Would you like more details or have any questions?

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Here are 5 related questions to expand your understanding:
1. How does temperature affect the molarity of a solution?
2. What is the difference between molarity and molality?
3. How would you prepare a 1 M solution of \( \text{CaCl}_2 \)?
4. How does the dissolution of \( \text{CaCl}_2 \) affect the conductivity of the solution?
5. What role does calcium chloride play in industrial applications?

**Tip:** Always ensure you convert volumes to liters when calculating molarity, as molarity is expressed in moles per liter.

What is the molarity of a solution that was prepared by dissolving 82.0 g of CaCl2 (molar mass = 111.1 g/mol) in enough water to make 812 mL of solution?

Learn how to calculate the molarity of a solution by dissolving 82.0 g of CaCl2 (molar mass 111.1 g/mol) in 812 mL of water. This problem covers key chemistry concepts like molarity, stoichiometry, and unit conversion. Suitable for high school students in Grades 10-12.

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