Although beginning salaries vary greatly according to your field of​ study, the equation s equals 2806.6 t plus 32 comma 558 can be used to approximate and to predict average beginning salaries for candidates with​ bachelor's degrees. The variable s is the starting salary and t is the number of years after 1995. Approximate when beginning salaries for candidates will be greater than ​$80,000.

The given equation is:

\[
s = 2806.6 \cdot t + 32,558
\]

where:
- $ s $ is the starting salary in dollars.
- $ t $ is the number of years after 1995.

We need to find when the beginning salary $ s $ will be greater than $80,000. Therefore, we set up the inequality:

\[
2806.6 \cdot t + 32,558 > 80,000
\]

To solve for $ t $:

1. Subtract 32,558 from both sides:

\[
2806.6 \cdot t > 80,000 - 32,558
\]

\[
2806.6 \cdot t > 47,442
\]

2. Divide both sides by 2806.6:

\[
t > \frac{47,442}{2806.6}
\]

Now, let's calculate the value:

\[
t > \frac{47,442}{2806.6} \approx 16.9
\]

Since $ t $ represents the number of years after 1995, we round up to the next whole number, because time in years should be an integer.

\[
t = 17
\]

So, beginning salaries will be greater than $80,000 approximately 17 years after 1995.

\[
1995 + 17 = 2012
\]

**Conclusion:** Beginning salaries will be greater than $80,000 starting from the year 2012.

Would you like more details or have any questions? 

Here are some related questions:

1. How would the result change if the starting salary threshold was $90,000 instead?
2. What does the slope 2806.6 represent in this context?
3. How would the equation change if the salaries increased at a faster rate?
4. What would the starting salary be in the year 2025?
5. Can this model predict future salaries accurately? Why or why not?

**Tip:** Always double-check your calculations when working with inequalities to ensure accuracy.

Learn how to predict beginning salaries using a linear equation model. Solve the equation s = 2806.6 t + 32,558 to approximate when starting salaries for candidates with bachelor's degrees will exceed $80,000. Suitable for students in Grades 7-9.

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