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count the electricity A and resistance R2

The problem involves finding the current (\( I \)) in the circuit and the resistance \( R_2 \). Here's how we can solve it using the provided information:

### Given Data:
- Voltage source \( V_{\text{total}} = 6.0 \, \text{V} \)
- Resistor \( R_1 = 22 \, \Omega \)
- Voltage across \( R_2 \), \( V_{R_2} = 2.4 \, \text{V} \)

### Step 1: Calculate the total current (\( I \)) in the circuit.

The resistors \( R_1 \) and \( R_2 \) are connected in series because the same current flows through both. The voltage drop across \( R_1 \) is calculated using Kirchhoff's Voltage Law (KVL), where the sum of voltage drops across resistors equals the total supplied voltage.

The total voltage is:
\[
V_{\text{total}} = V_{R_1} + V_{R_2}
\]
Thus, the voltage across \( R_1 \) is:
\[
V_{R_1} = V_{\text{total}} - V_{R_2} = 6.0 \, \text{V} - 2.4 \, \text{V} = 3.6 \, \text{V}
\]

### Step 2: Use Ohm's Law to find the current.

Now, using Ohm's Law \( V = IR \), we can calculate the current in the circuit. The current \( I \) is the same through both resistors in a series circuit, so we use \( R_1 \) and \( V_{R_1} \):

\[
I = \frac{V_{R_1}}{R_1} = \frac{3.6 \, \text{V}}{22 \, \Omega} = 0.1636 \, \text{A}
\]

### Step 3: Find the resistance \( R_2 \).



Calculate the current in the circuit and the resistance of resistor R2.

Explore the step-by-step process to determine the current flowing through a series circuit and calculate the resistance of the second resistor using Ohm's Law and Kirchhoff's Voltage Law. This advanced problem is suitable for college-level studies in electrical engineering or physics.

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