Math Problem Statement

3x4 − 8x3 + 3 = 0, [2, 3] (a) Explain how we know that the given equation must have a solution in the given interval. Let f(x) = 3x4 − 8x3 + 3. The polynomial f is continuous on [2, 3], f(2) = -13

Correct: Your answer is correct. < 0, and f(3) = 30

Correct: Your answer is correct.

0, so by the Intermediate Value Theorem, there is a number c in (2, 3) such that f(c) = 0

Correct: Your answer is correct. . In other words, the equation 3x4 − 8x3 + 3 = 0 has a solution in [2, 3]. (b) Use Newton's method to approximate the solution correct to six decimal places.

Solution

To use Newton's method to approximate the solution of the equation f(x)=3x48x3+3=0f(x) = 3x^4 - 8x^3 + 3 = 0 correct to six decimal places, we need the derivative of f(x)f(x), which will be used iteratively to find the root.

  1. Define f(x)f(x) and f(x)f'(x): f(x)=3x48x3+3f(x) = 3x^4 - 8x^3 + 3 f(x)=12x324x2f'(x) = 12x^3 - 24x^2

  2. Newton's Method Formula: Newton's method states that the next approximation xn+1x_{n+1} is given by: xn+1=xnf(xn)f(xn)x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}

  3. Initial Guess: Since we know the solution lies within the interval [2,3][2, 3], we can start with an initial guess of x0=2.5x_0 = 2.5.

  4. Iterative Computation: We apply the formula iteratively, recalculating xx until the value converges to six decimal places.

Let me compute this for you.Using Newton's method, we approximate the solution to the equation f(x)=3x48x3+3=0f(x) = 3x^4 - 8x^3 + 3 = 0 as x2.610452x \approx 2.610452, correct to six decimal places.

Would you like further details on this process, or do you have any questions?

Here are some related questions that build on this topic:

  1. How does Newton's method converge, and what factors influence its speed of convergence?
  2. What role does the choice of initial guess play in Newton's method?
  3. Can Newton's method fail to converge, and under what conditions?
  4. How is the Intermediate Value Theorem useful in identifying intervals for solutions?
  5. What other methods can be used to approximate roots of polynomials?

Tip: In Newton's method, the closer your initial guess is to the actual root, the faster the method will converge.

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Math Problem Analysis

Mathematical Concepts

Polynomials
Root Approximation
Calculus

Formulas

Newton's method formula: x_(n+1) = x_n - f(x_n) / f'(x_n)
Derivative of polynomial: f'(x) = 12x^3 - 24x^2

Theorems

Intermediate Value Theorem

Suitable Grade Level

College level Calculus or Advanced High School Calculus