Math Problem Statement
answer #12, #14, and #16
Solution
Let's solve each of the requested problems:
#12: Zeros: and
To write the polynomial with real coefficients, remember that complex roots come in conjugate pairs. Therefore, the zeros are , , and .
The factors corresponding to these zeros are:
Combine the complex conjugate factors:
Now multiply this with :
Expand:
Final polynomial:
#14: Zeros: (multiplicity 3), (multiplicity 1)
The factors for the zeros are:
Multiply these together:
Now multiply by :
Expand:
Combine like terms:
Final polynomial:
#16: Zeros: (multiplicity 2), (multiplicity 1)
Since is a root, its conjugate must also be a root.
The factors corresponding to these zeros are:
Simplify the complex conjugate pair:
Now multiply this with :
First expand :
Now multiply this with :
Expand:
Combine like terms:
Final polynomial:
Recap of Results:
- #12:
- #14:
- #16:
Would you like more detailed steps or additional questions?
Here are five related problems for practice:
- How do you verify that a polynomial has the given roots?
- Write a polynomial where the zeros are , and .
- Solve for a polynomial with and as roots.
- Write a polynomial with (multiplicity 2) and (multiplicity 1).
- What happens to the degree of a polynomial when you increase a root's multiplicity?
Tip: Always check for conjugate pairs when working with complex roots and real coefficients!
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Math Problem Analysis
Mathematical Concepts
Polynomials
Complex Numbers
Roots of Polynomials
Conjugate Pairs
Formulas
Product of roots for quadratic polynomials: (x - root1)(x - root2)
Complex root conjugate pair expansion: (x - (a + bi))(x - (a - bi)) = (x - a)^2 + b^2
Root multiplicity effect on polynomial degree
Theorems
Fundamental Theorem of Algebra
Properties of Polynomials with Real Coefficients
Suitable Grade Level
Grades 10-12
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