The image contains a math problem, and it appears to be in Chinese. From what I can make out, it seems to involve a polynomial expression. I'll break down the problem and solve it based on the visible content.

The equation given is:

$a(x^2 - x + 3x) + b(x^2 + x) + x^2 - 5 \quad \text{when} \quad x = -2$

You are asked to find the value of this expression when $x = -2$, and there is some missing context about values for $a$ and $b$.

Let's substitute $x = -2$ and simplify the expression, assuming the coefficients $a$ and $b$ are not yet given.

1. Simplify each term inside the parentheses:
   • $x^2 - x + 3x = x^2 + 2x$
   • $x^2 + x$

So the expression becomes:

$a(x^2 + 2x) + b(x^2 + x) + x^2 - 5$

Now, substituting $x = -2$:

$a((-2)^2 + 2(-2)) + b((-2)^2 + (-2)) + (-2)^2 - 5$

2. Calculate the terms:
   • $(-2)^2 = 4$
   • $2(-2) = -4$
   • $(-2)^2 = 4$
   • $-2 = -2$
   • $(-2)^2 - 5 = 4 - 5 = -1$

Now, the expression becomes:

$a(4 - 4) + b(4 - 2) + 4 - 5 = 0a + 2b - 1$

This simplifies to:

$2b - 1$

So, the value of the expression when $x = -2$ is $2b - 1$.

Do you want further details or help with a specific part of the problem?