Math Problem Statement

The coefficient of x^2 is -147 in the expansion of (kx-1- (7)/9kx) (1-3x)^7. What is K

Solution

To find the value of kk in the expression (kx179kx)(13x)7(kx - 1 - \frac{7}{9}kx)(1 - 3x)^7 where the coefficient of x2x^2 is 147-147, we need to expand the expression and collect terms involving x2x^2.

Step 1: Expand Each Part Separately

Consider the expression:

(kx179kx)(13x)7(kx - 1 - \frac{7}{9}kx)(1 - 3x)^7

This consists of two parts:

  1. (kx179kx)=kx179kx=(k79k)x1=2k9x1(kx - 1 - \frac{7}{9}kx) = kx - 1 - \frac{7}{9}kx = \left(k - \frac{7}{9}k\right)x - 1 = \frac{2k}{9}x - 1
  2. The binomial expansion of (13x)7(1 - 3x)^7.

Step 2: Binomial Expansion of (13x)7(1 - 3x)^7

The binomial theorem states:

(13x)7=n=07(7n)(1)7n(3x)n=n=07(7n)(3x)n(1 - 3x)^7 = \sum_{n=0}^{7} \binom{7}{n} (1)^{7-n}(-3x)^n = \sum_{n=0}^{7} \binom{7}{n} (-3x)^n

Focusing on the terms involving xx and x2x^2:

  • The term for n=1n = 1 (the xx term) is: (71)(3x)1=7(3x)=21x\binom{7}{1}(-3x)^1 = 7(-3x) = -21x

  • The term for n=2n = 2 (the x2x^2 term) is: (72)(3x)2=21(9x2)=189x2\binom{7}{2}(-3x)^2 = 21(9x^2) = 189x^2

Step 3: Multiply and Collect x2x^2 Terms

Now we multiply the simplified first part (2k9x1)\left(\frac{2k}{9}x - 1\right) by the expansion:

(2k9x1)(121x+189x2+)\left(\frac{2k}{9}x - 1\right)(1 - 21x + 189x^2 + \cdots)

We are interested in the coefficient of x2x^2. The x2x^2 terms come from:

  1. The product of 1-1 (constant term) and 189x2189x^2:
    1189x2=189x2-1 \cdot 189x^2 = -189x^2

  2. The product of 2k9x\frac{2k}{9}x and 21x-21x (the xx term):
    2k9x(21x)=2k9(21)x2=42k9x2\frac{2k}{9}x \cdot (-21x) = \frac{2k}{9} \cdot (-21) x^2 = -\frac{42k}{9}x^2

Step 4: Sum Up the Coefficients of x2x^2

The total coefficient of x2x^2 is:

18942k9-189 - \frac{42k}{9}

According to the problem, this coefficient is 147-147:

18942k9=147-189 - \frac{42k}{9} = -147

Step 5: Solve for kk

  1. Add 189 to both sides:

    42k9=147+189-\frac{42k}{9} = -147 + 189

    42k9=42-\frac{42k}{9} = 42

  2. Multiply both sides by 1-1:

    42k9=42\frac{42k}{9} = -42

  3. Multiply both sides by 9:

    42k=42×942k = -42 \times 9

    42k=37842k = -378

  4. Divide both sides by 42:

    k=37842=9k = \frac{-378}{42} = -9

Answer

The value of kk is:

9\boxed{-9}

Would you like more details or have any questions?

Here are 5 related questions to explore further:

  1. How do you expand a binomial expression using the binomial theorem?
  2. What are some common applications of the binomial theorem in probability and statistics?
  3. How can we use the coefficients of binomial expansions to solve combinatorial problems?
  4. What is the general formula for expanding a polynomial raised to a power?
  5. How can we find the coefficient of a particular term in a polynomial expansion without expanding the entire expression?

Tip: Always carefully consider how terms multiply together when expanding polynomials, as mistakes in signs or coefficients are common.

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Math Problem Analysis

Mathematical Concepts

Algebra
Polynomial Expansion
Binomial Theorem

Formulas

Binomial expansion: (1 - x)^n = ∑(n choose k) (-x)^k
Coefficient of x^2 in polynomial expansions
Basic algebraic manipulations

Theorems

Binomial Theorem

Suitable Grade Level

Grades 11-12