Math Problem Statement

Plot the point given in polar coordinates,
( − 5 , 7 π 2 ) , and then give three different expressions for the point such that

1 2 3 4 5 6 -1 -2 -3 -4 -5 -6 1 2 3 4 5 6 -1 -2 -3 -4 -5 -6 Clear All Draw: Dot (a)
r < 0 and
0 ≤ θ

< 2 π

r

Correct

θ

Incorrect

(b)
r

0 and
− 2 π ≤ θ

< 0

r

Correct

θ

(c)
r

0 and
2 π ≤ θ

< 4 π

r

Correct

θ

Solution

To plot the point and find three equivalent expressions for the point given in polar coordinates, let's analyze the point:

Given Point:
(r,θ)=(5,7π2)(r, \theta) = (-5, \frac{7\pi}{2})

The negative radius r=5r = -5 indicates that the point is actually in the opposite direction from θ=7π2\theta = \frac{7\pi}{2}, meaning we can convert this to a positive radius by adjusting θ\theta by π\pi radians.

Step-by-Step Solutions

Plotting the Point

  1. Convert θ=7π2\theta = \frac{7\pi}{2} into an equivalent angle between 00 and 2π2\pi: 7π2=2π+3π2\frac{7\pi}{2} = 2\pi + \frac{3\pi}{2} So, the direction of this point is equivalent to θ=3π2\theta = \frac{3\pi}{2} with a radius of 5-5, pointing 5 units in the opposite direction from θ=3π2\theta = \frac{3\pi}{2}.

Finding Equivalent Expressions

We will rewrite this point in three different forms as requested.

  1. Form (a): r<0r < 0 and 0θ<2π0 \leq \theta < 2\pi

    • r=5r = -5 and θ=3π2\theta = \frac{3\pi}{2} satisfy this condition.
    • Answer for (a): (r,θ)=(5,3π2)(r, \theta) = (-5, \frac{3\pi}{2})
  2. Form (b): r>0r > 0 and 2πθ<0-2\pi \leq \theta < 0

    • To make rr positive, we take r=5r = 5.
    • Since θ=3π2\theta = \frac{3\pi}{2} in the opposite direction gives a positive radius of 5, we subtract 2π2\pi to bring it into the range [2π,0)[-2\pi, 0): θ=π2\theta = -\frac{\pi}{2}
    • Answer for (b): (r,θ)=(5,π2)(r, \theta) = (5, -\frac{\pi}{2})
  3. Form (c): r>0r > 0 and 2πθ<4π2\pi \leq \theta < 4\pi

    • Use r=5r = 5 and add 2π2\pi to θ=3π2\theta = \frac{3\pi}{2} to get an equivalent angle in the range 2πθ<4π2\pi \leq \theta < 4\pi: θ=7π2\theta = \frac{7\pi}{2}
    • Answer for (c): (r,θ)=(5,7π2)(r, \theta) = (5, \frac{7\pi}{2})

Summary of Equivalent Points:

  • (a) (r,θ)=(5,3π2)(r, \theta) = (-5, \frac{3\pi}{2})
  • (b) (r,θ)=(5,π2)(r, \theta) = (5, -\frac{\pi}{2})
  • (c) (r,θ)=(5,7π2)(r, \theta) = (5, \frac{7\pi}{2})

Would you like further details on polar coordinate transformations?

Here are some related questions to explore:

  1. How do you convert between polar and Cartesian coordinates?
  2. Why is it useful to have multiple representations of polar coordinates?
  3. What is the effect of changing rr and θ\theta on the plotted position?
  4. How can you visualize negative angles in polar coordinates?
  5. What are other applications of polar coordinates in mathematics?

Tip: In polar coordinates, a negative radius reflects the point across the origin in the opposite direction of the angle, making conversions to positive radii straightforward with angle adjustments.

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Math Problem Analysis

Mathematical Concepts

Polar Coordinates
Angle Conversion
Negative Radius

Formulas

θ = θ + 2πn (angle adjustment formula)
r = -r (reflecting point across the origin)

Theorems

Polar Coordinate Conversion Theorem

Suitable Grade Level

Grades 10-12