Math Problem Statement

Write an equation in point-slope form of the line that passes through the point $\left(5,\ -12\right)$ and has a slope of $m=-\frac{2}{5}$ . $y-$ $=$
$\text{(}x-$ $\text{)}$

Question 2 Graph the line. Keyboard Instructions Initial graph state The horizontal axis goes from -10.4 to 10.4 with ticks spaced every 1 unit(s). The vertical axis goes from -20.4 to 8.4 with ticks spaced every 2 unit(s).

Solution

To write the equation of a line in point-slope form, we use the formula:

yy1=m(xx1)y - y_1 = m(x - x_1)

where (x1,y1)(x_1, y_1) is a point on the line, and mm is the slope.

Given:

  • Point: (x1,y1)=(5,12)(x_1, y_1) = (5, -12)
  • Slope: m=25m = -\frac{2}{5}

Substitute these values into the formula:

y(12)=25(x5)y - (-12) = -\frac{2}{5}(x - 5)

Simplify:

y+12=25(x5)y + 12 = -\frac{2}{5}(x - 5)

The equation in point-slope form is:

y+12=25(x5)y + 12 = -\frac{2}{5}(x - 5)

Graphing the Line

To graph this line, you could:

  1. Start at the point (5,12)(5, -12).
  2. Use the slope 25-\frac{2}{5}, which means move down 2 units and right 5 units to find another point.
  3. Draw the line through these points.

Would you like more details, or do you have questions?


Related Questions:

  1. What is the general form of a linear equation?
  2. How do you convert from point-slope form to slope-intercept form?
  3. What does the slope represent in a real-world context?
  4. How do you graph a line given a point and a slope?
  5. How can you check if a point lies on a given line?

Tip: In point-slope form, the point used does not have to be on the y-axis, making it very flexible for any point on the line.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Point-Slope Form

Formulas

Point-Slope form: y - y1 = m(x - x1)

Theorems

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Suitable Grade Level

Grades 8-10