The problem in the image asks for the equation of a line in point-slope form that passes through the point $(-4, 1)$ and has a slope $m = 3$.

The point-slope form of the equation of a line is given by:

$y - y_1 = m(x - x_1)$

Where:

• $(x_1, y_1)$ is a point on the line.
• $m$ is the slope of the line.

In this case, we have:

• $x_1 = -4$
• $y_1 = 1$
• $m = 3$

Substitute these values into the point-slope form equation:

$y - 1 = 3(x - (-4))$

Simplify the equation:

$y - 1 = 3(x + 4)$

This is the equation of the line in point-slope form.

Would you like further details or have any other questions?

Here are 5 related questions for practice:

1. How would the equation change if the slope were negative?
2. What is the equation in slope-intercept form?
3. How do you convert point-slope form to standard form?
4. Can you find another point on this line using the equation?
5. What happens to the line if the slope becomes zero?

Tip: In point-slope form, the signs of the coordinates of the point always reverse when substituted into the equation.