To determine which point would not be a solution to the given system of inequalities, we need to test each point against both inequalities:

1. $y < 2x + 2$
2. $y \leq -\frac{5}{2}x - 5$

Testing Each Point

Let's evaluate each point:

1. Point $(-4, -8)$

• For $y < 2x + 2$: $-8 < 2(-4) + 2 = -8 + 2 = -6 \quad \text{(False)}$
• Since this fails the first inequality, this point is not a solution.

Checking the Other Points for Completeness

Although $(-4, -8)$ already fails the conditions, we can quickly verify the others for understanding:

2. Point $(-2, -4)$

• For $y < 2x + 2$: $-4 < 2(-2) + 2 = -4 + 2 = -2 \quad \text{(True)}$
• For $y \leq -\frac{5}{2}x - 5$: $-4 \leq -\frac{5}{2}(-2) - 5 = 5 - 5 = 0 \quad \text{(True)}$

3. Point $(-8, -1)$

• For $y < 2x + 2$: $-1 < 2(-8) + 2 = -16 + 2 = -14 \quad \text{(False)}$
• This also fails the first inequality.

4. Point $(-2, -8)$

• For $y < 2x + 2$: $-8 < 2(-2) + 2 = -4 + 2 = -2 \quad \text{(True)}$
• For $y \leq -\frac{5}{2}x - 5$: $-8 \leq -\frac{5}{2}(-2) - 5 = 5 - 5 = 0 \quad \text{(True)}$

Conclusion

The points $(-4, -8)$ and $(-8, -1)$ both fail to satisfy at least one inequality. Based on the first failed check, the answer is:

• $(-4, -8)$