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Point \( J \) is located at \(-13\), and points \( K \) and \( L \) are each 10 units away from \( J \). To determine their positions, we can add and subtract 10 from \(-13\):

1. **Finding \( K \)**:
   \[
   K = -13 + 10 = -3
   \]

2. **Finding \( L \)**:
   \[
   L = -13 - 10 = -23
   \]

So, the coordinates of points \( K \) and \( L \) are:

- \( K = -3 \)
- \( L = -23 \)

Would you like more details on this solution or have any other questions?

### Related Questions:
1. How do you find points that are a certain distance away on a number line?
2. What is the general process for translating points on a number line?
3. How do you plot points like \( K \) and \( L \) on a Cartesian plane?
4. What is the difference between positive and negative translations on a number line?
5. How would this change if \( J \) were located at a different point, like \( 5 \)?

### Tip:
When working with distances on a number line, adding or subtracting the distance will help you find the new points quickly.

Point J is located at −13. Points K and L are each 10 units away from point J. Plot point K and point L on the number line.

Learn how to plot points K and L on a number line, given that point J is located at −13, and K and L are each 10 units away. This problem covers basic number line concepts and coordinate plotting, suitable for students in Grades 6-8.

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