To solve this task, we need to plot points for the equation $y = -3x + 6$ when $x = -1$ and when $x = 1$.

Let's go through the calculations:

1. For $x = -1$: $y = -3(-1) + 6 = 3 + 6 = 9$ So, the point when $x = -1$ is $(-1, 9)$.

2. For $x = 1$: $y = -3(1) + 6 = -3 + 6 = 3$ So, the point when $x = 1$ is $(1, 3)$.

The two points to plot on the graph are:

• $(-1, 9)$
• $(1, 3)$

Would you like further details on graphing this line or have additional questions about linear equations?

Here are some related questions for further exploration:

1. How do you determine the slope of a linear equation?
2. What does the y-intercept of this line represent?
3. How would the graph change if the equation were $y = 3x + 6$ instead?
4. What are the x- and y-intercepts of this line?
5. How can you check if a point lies on the line of this equation?

Tip: Remember that in the equation $y = mx + b$, $m$ represents the slope and $b$ is the y-intercept, which is where the line crosses the y-axis.