Math Problem Statement

A lamina is subjected to plane stress condition as shown in figure. Which one or more of the following options is/are correct?

Solution

The problem describes a lamina subjected to a plane stress condition, with stresses applied at 60MPa60 \, \text{MPa} and 100MPa100 \, \text{MPa}. We need to check which of the given options regarding the normal stress on planes MN and the plane perpendicular to MN are correct.

To analyze the stresses on plane MN, we can apply the equations of plane stress transformation. Specifically, the normal stress σn\sigma_n and shear stress τn\tau_n on a plane at an angle θ\theta to the x-axis are given by:

σnormal=σxcos2(θ)+σysin2(θ)+2τxysin(θ)cos(θ)\sigma_{\text{normal}} = \sigma_x \cos^2(\theta) + \sigma_y \sin^2(\theta) + 2\tau_{xy} \sin(\theta) \cos(\theta) σshear=(σyσx)sin(θ)cos(θ)+τxy(cos2(θ)sin2(θ))\sigma_{\text{shear}} = (\sigma_y - \sigma_x) \sin(\theta) \cos(\theta) + \tau_{xy} (\cos^2(\theta) - \sin^2(\theta))

Here:

  • σx=100MPa\sigma_x = 100 \, \text{MPa} (the normal stress along the x-axis)
  • σy=60MPa\sigma_y = 60 \, \text{MPa} (the normal stress along the y-axis)
  • τxy=0MPa\tau_{xy} = 0 \, \text{MPa} (as no shear stress is given)
  • θ=30\theta = 30^\circ (angle of MN from the horizontal axis)

Let's calculate the normal stresses for the planes MN and the plane perpendicular to MN.

I'll work through the math to determine which options are correct.The normal stresses calculated are as follows:

  • The normal stress on plane MN is approximately 90MPa90 \, \text{MPa}.
  • The normal stress on the plane perpendicular to MN is approximately 70MPa70 \, \text{MPa}.

Now, let's analyze the given options based on these results:

  • (A) Normal stress in plane MN is 60MPa60 \, \text{MPa} (Tensile): This is incorrect, as the normal stress on plane MN is 90MPa90 \, \text{MPa}, not 60MPa60 \, \text{MPa}.
  • (B) Normal stress in plane perpendicular to MN is 20MPa20 \, \text{MPa} (Compressive): This is incorrect, since the normal stress perpendicular to MN is approximately 70MPa70 \, \text{MPa}.
  • (C) Normal stress in plane MN is 75MPa75 \, \text{MPa} (Tensile): This is incorrect, the actual stress is 90MPa90 \, \text{MPa}.
  • (D) Normal stress in plane perpendicular to MN is 35MPa35 \, \text{MPa} (Compressive): This is incorrect, as the stress is 70MPa70 \, \text{MPa}.

Thus, none of the options provided are correct.

Would you like more details or have any questions?

Here are five related questions to expand your understanding:

  1. How does shear stress influence the normal stress on an inclined plane?
  2. What are Mohr's circle representations for plane stress problems?
  3. How do we calculate the shear stress on a plane at an angle θ\theta?
  4. Why do we need to use transformation equations for stress analysis?
  5. What happens if there is a non-zero shear stress τxy\tau_{xy}?

Tip: Plane stress problems are easier to visualize if you use Mohr's circle, which graphically represents stress transformations.

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Math Problem Analysis

Mathematical Concepts

Plane Stress Transformation
Stress Analysis

Formulas

Normal stress formula: σn = σx cos²θ + σy sin²θ + 2τxy sinθ cosθ
Shear stress formula: τn = (σy - σx) sinθ cosθ + τxy (cos²θ - sin²θ)

Theorems

Stress Transformation Theorem

Suitable Grade Level

Undergraduate (Engineering)