write two numbers so that the value of the digit 9 in the second number is 10 times the value of the digit 9 in the first number

To solve this, we need to write two numbers where the value of the digit 9 in the second number is 10 times the value of the digit 9 in the first number.

The value of a digit in a number depends on its place value. For example:
- In the number 90, the value of 9 is \( 9 \times 10 = 90 \).
- In the number 900, the value of 9 is \( 9 \times 100 = 900 \).

Let’s define two numbers:
- The first number: 90, where the value of 9 is \( 9 \times 10 = 90 \).
- The second number: 900, where the value of 9 is \( 9 \times 100 = 900 \).

In this case, the value of the 9 in the second number (900) is exactly 10 times the value of the 9 in the first number (90).

Thus, the two numbers are **90** and **900**.

Would you like more details or have any questions? Here are 5 questions to explore further:
1. What is the place value system in mathematics?
2. How does the place value affect the value of a digit in a number?
3. Can you find other pairs of numbers with similar properties involving other digits?
4. How can we express a number using powers of 10?
5. What are some real-world applications of understanding place values?

**Tip:** When comparing the values of digits in different numbers, always consider their positions and place values to make accurate comparisons.

Write two numbers so that the value of the digit 9 in the second number is 10 times the value of the digit 9 in the first number.

Explore how to write two numbers such that the value of the digit 9 in the second number is 10 times the value of the digit 9 in the first number. This solution uses the place value system, showing how position affects the value of digits. Suitable for Grades 4-6 students.

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