Math Problem Statement

write two numbers so that the value of the digit 9 in the second number is 10 times the value of the digit 9 in the first number

Solution

To solve this, we need to write two numbers where the value of the digit 9 in the second number is 10 times the value of the digit 9 in the first number.

The value of a digit in a number depends on its place value. For example:

  • In the number 90, the value of 9 is 9×10=909 \times 10 = 90.
  • In the number 900, the value of 9 is 9×100=9009 \times 100 = 900.

Let’s define two numbers:

  • The first number: 90, where the value of 9 is 9×10=909 \times 10 = 90.
  • The second number: 900, where the value of 9 is 9×100=9009 \times 100 = 900.

In this case, the value of the 9 in the second number (900) is exactly 10 times the value of the 9 in the first number (90).

Thus, the two numbers are 90 and 900.

Would you like more details or have any questions? Here are 5 questions to explore further:

  1. What is the place value system in mathematics?
  2. How does the place value affect the value of a digit in a number?
  3. Can you find other pairs of numbers with similar properties involving other digits?
  4. How can we express a number using powers of 10?
  5. What are some real-world applications of understanding place values?

Tip: When comparing the values of digits in different numbers, always consider their positions and place values to make accurate comparisons.

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Math Problem Analysis

Mathematical Concepts

Place Value System
Multiplication
Powers of 10

Formulas

Place Value of a digit = Digit × Position value
Position value = 10^n, where n is the position of the digit from the right (starting from 0)

Theorems

Place Value Theorem

Suitable Grade Level

Grades 4-6