f()={x+1    ifx <0                                                                                                                                                                                      3               ifx=0                                                                                                                                                                         x-2            ifx>0                                                                                                                                               

The function you've provided appears to be a piecewise function. I'll rewrite it with proper formatting:

\[
f(x) = 
\begin{cases} 
x + 1 & \text{if } x < 0 \\
3 & \text{if } x = 0 \\
x - 2 & \text{if } x > 0
\end{cases}
\]

### Explanation:
- **If \( x < 0 \)**, the function evaluates as \( f(x) = x + 1 \).
- **If \( x = 0 \)**, the function evaluates as \( f(x) = 3 \).
- **If \( x > 0 \)**, the function evaluates as \( f(x) = x - 2 \).

Would you like me to evaluate this function at specific points or explain how it behaves over different intervals?

Here are 5 related questions to deepen your understanding:

1. What is the value of \( f(-2) \) using the piecewise function?
2. How does the function behave as \( x \to 0 \) from both the left and the right?
3. What is the graph of this piecewise function like?
4. How would you describe the continuity of \( f(x) \)?
5. How can you modify the function so that it is continuous for all \( x \)?

**Tip:** Piecewise functions often change behavior at specific points. Always carefully check which condition applies when calculating values!

f() = {x + 1 if x < 0, 3 if x = 0, x - 2 if x > 0}

Learn how to define and evaluate the piecewise function f(x) = {x + 1 for x < 0, 3 for x = 0, x - 2 for x > 0}. This problem covers key concepts in algebra and function evaluation, suitable for students in Grades 9-12.

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