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The function \( f(x) \) is defined piecewise as follows:

\[
f(x) = \begin{cases} 
3x + 1 & \text{for } x \neq -2 \\
2 & \text{for } x = -2 
\end{cases}
\]

To find \( f(-2) \), we use the part of the function where \( x = -2 \). According to the second case:

\[
f(-2) = 2
\]

Thus, \( f(-2) = 2 \).

Would you like further details or have any questions?

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Here are 5 related questions to expand on this concept:
1. What is \( f(0) \) for this function?
2. How would you describe the behavior of this piecewise function as \( x \to -2 \)?
3. What would the graph of this piecewise function look like?
4. How can we check the continuity of \( f(x) \) at \( x = -2 \)?
5. What happens if \( f(x) \) had a different rule for \( x = -2 \)?

**Tip:** When dealing with piecewise functions, always check which case applies based on the value of \( x \).

The function \( f(x) \) is defined piecewise as follows:

\[
f(x) = \begin{cases} 
3x + 1 & \text{for } x \neq -2 \\
2 & \text{for } x = -2 
\end{cases}
\]

Find \( f(-2) \).

Learn how to evaluate the piecewise function defined as f(x) = 3x + 1 for x ≠ -2 and f(x) = 2 for x = -2. This problem involves understanding piecewise functions and function evaluation, suitable for students in Grades 7-9.

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