Math Problem Statement

Given a piecewise function f(x) with conditions for x ≤ 3 and x > 3, evaluate f(3) and determine the value of 'a' when f(a) = 5.

Solution

The image contains mathematical problems related to piecewise functions and evaluating them under specific conditions. I'll analyze and explain the problems step by step.


1. Analyzing the piecewise function f(x)f(x):

From the highlighted portion of the image:

  • The function f(x)f(x) is defined as: \begin{cases} x + 2 & \text{if } x \leq 3 \\ x^2 - 10 & \text{if } x > 3 \end{cases}$$

2. Evaluating f(3)f(3):

  • According to the definition, when x3x \leq 3, we use the equation f(x)=x+2f(x) = x + 2. f(3)=3+2=5f(3) = 3 + 2 = 5

3. Finding the value of aa when f(a)=5f(a) = 5:

  • Case 1: If a3a \leq 3, use f(x)=x+2f(x) = x + 2: f(a)=a+2=5a=3f(a) = a + 2 = 5 \quad \Rightarrow \quad a = 3

  • Case 2: If a>3a > 3, use f(x)=x210f(x) = x^2 - 10: f(a)=a210=5a2=15a=±15.f(a) = a^2 - 10 = 5 \quad \Rightarrow \quad a^2 = 15 \quad \Rightarrow \quad a = \pm\sqrt{15}. However, since a>3a > 3, we only consider the positive root: a=15.a = \sqrt{15}.

So, a=3a = 3 or a=15a = \sqrt{15}.


4. Determining the correct answer:

The question highlights a=4a = 4, which satisfies:

  • Case 2: f(4)=4210=1610=6f(4) = 4^2 - 10 = 16 - 10 = 6, which is incorrect for f(a)=5f(a) = 5.

The accurate solution seems to indicate a=3a = 3 or a=15a = \sqrt{15}.


Would you like me to analyze another part of the image or explain further? Let me know!


Relative Questions:

  1. What is the role of piecewise functions in real-life applications?
  2. How can we derive solutions when piecewise functions have multiple domains?
  3. Why is it important to consider constraints like x>3x > 3 in piecewise functions?
  4. What happens when aa is at the boundary (e.g., x=3x = 3) in such functions?
  5. How do we evaluate piecewise functions involving inequalities?

Tip:

Always double-check which part of a piecewise function applies to your input value to avoid mistakes!

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Math Problem Analysis

Mathematical Concepts

Piecewise functions
Evaluation of functions
Quadratic equations

Formulas

Piecewise definition of f(x): f(x) = {x + 2 if x ≤ 3; x^2 - 10 if x > 3}
Equation: a^2 - 10 = 5 to find 'a'
Boundary conditions: x ≤ 3 and x > 3

Theorems

Properties of piecewise functions
Quadratic solutions for a^2 - c = 0

Suitable Grade Level

Grades 9-11