Math Problem Statement

A block sliding along a flat horizontal surface at an initial velocity of 2.0 m/s experiences a constant resistive force of 4.0 N that brings it to rest in a distance of 2.0 m. What is the mass of the block?

Solution

The problem in the image involves a block sliding along a flat horizontal surface with an initial velocity of v0=2.0m/sv_0 = 2.0 \, \text{m/s} and experiencing a constant resistive force of F=4.0NF = 4.0 \, \text{N}, which brings the block to rest after covering a distance d=2.0md = 2.0 \, \text{m}.

We are asked to find the mass mm of the block.

Step-by-step solution:

  1. Using the work-energy principle:
    The work done by the resistive force brings the block to rest. According to the work-energy theorem: W=ΔKW = \Delta K where WW is the work done by the force, and ΔK\Delta K is the change in kinetic energy.

    The initial kinetic energy KiK_i is: Ki=12mv02K_i = \frac{1}{2} m v_0^2 Since the block comes to rest, the final kinetic energy Kf=0K_f = 0. Therefore, the change in kinetic energy is: ΔK=KfKi=012mv02=12mv02\Delta K = K_f - K_i = 0 - \frac{1}{2} m v_0^2 = -\frac{1}{2} m v_0^2

  2. Calculating the work done by the resistive force:
    The work done by a constant force is given by: W=FdW = F \cdot d where F=4.0NF = 4.0 \, \text{N} and d=2.0md = 2.0 \, \text{m}. Therefore: W=4.0N×2.0m=8.0JW = 4.0 \, \text{N} \times 2.0 \, \text{m} = 8.0 \, \text{J}

  3. Equating the work done to the change in kinetic energy:
    According to the work-energy theorem, the work done by the force is equal to the negative of the change in kinetic energy: 12mv02=W-\frac{1}{2} m v_0^2 = W Substituting the values: 12m(2.0m/s)2=8.0J-\frac{1}{2} m (2.0 \, \text{m/s})^2 = -8.0 \, \text{J} Simplifying: 12m×4=8.0\frac{1}{2} m \times 4 = 8.0 2m=8.02m = 8.0 m=4.0kgm = 4.0 \, \text{kg}

Final Answer:

The mass of the block is 4.0kg\boxed{4.0 \, \text{kg}}.

Would you like more details or have any questions?

Here are 5 related questions to explore further:

  1. What is the significance of the work-energy theorem in mechanics?
  2. How does the resistive force impact the motion of objects?
  3. Can you derive the formula for work done by a force using basic principles of energy?
  4. What would happen to the stopping distance if the resistive force doubled?
  5. How does this problem change if the surface is inclined?

Tip: Always ensure that all forces acting on a body are accounted for when solving problems involving work and energy.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Kinematics
Work-Energy Principle

Formulas

Work-Energy Theorem: W = ΔK
Kinetic Energy: K = 1/2 mv^2
Work done by force: W = F × d

Theorems

Work-Energy Theorem

Suitable Grade Level

Grades 10-12