https://file.aiquickdraw.com/mathbot/file/1728573648506tfw6xv01.jpg

Let's analyze the problem from the image:

We have a block with mass \( m = 10 \, \text{kg} \) on a rough surface. The block is pulled by a force \( F = 12 \, \text{N} \) horizontally to the right. The static friction coefficient between the block and the surface is \( \mu_s = 0.2 \) and the kinetic friction coefficient is \( \mu_k = 0.1 \).

The task is to find:
1. The normal force (\( F_N \)).
2. The frictional force between the block and the floor.
3. The acceleration of the block.

### Part (a) - Normal Force (\( F_N \))
The normal force is equal to the gravitational force acting on the block since there is no vertical movement:
\[
F_N = m \cdot g = 10 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 = 98 \, \text{N}
\]

### Part (b) - Frictional Force
There are two possibilities for friction: static friction (if the block is not moving) and kinetic friction (if the block moves).

#### Static Friction
The maximum static friction is given by:
\[
f_{\text{static max}} = \mu_s \cdot F_N = 0.2 \cdot 98 \, \text{N} = 19.6 \, \text{N}
\]
Since the applied force is only \( F = 12 \, \text{N} \), the static friction can balance this force, preventing the block from moving. So, the frictional force in this case is:
\[
f_{\text{static}} = 12 \, \text{N}
\]
Thus, the block does not move, and static friction is \( 12 \, \text{N} \).

### Part (c) - Acceleration
Since the static friction is enough to prevent movement, the acceleration of the block is:
\[
a = 0 \, \text{m/s}^2
\]

Would you like further clarification on any part of the solution? 

Here are five related questions to explore further:
1. What would happen if the applied force exceeded the maximum static friction?
2. How do we calculate the acceleration if the block begins to move?
3. How would increasing the kinetic friction coefficient affect the problem?
4. Can we have a situation where both static and kinetic friction are involved?
5. How do we calculate the net force when the block is moving?

**Tip:** Always check whether static friction is enough to prevent motion before applying kinetic friction principles.

Benda bermassa m = 10 kg berada di atas lantai kasar ditarik oleh gaya F = 12 N ke arah kanan. Jika koefisien gesekan statis antara benda dan lantai adalah 0.2 dengan koefisien gesekan kinetis 0.1 tentukan besarnya: a) Gaya normal b) Gaya gesek antara benda dan lantai c) Percepatan gerak benda

Solve a physics problem involving a 10 kg object pulled by a 12 N force on a rough surface. Learn how to calculate the normal force, frictional forces (static and kinetic), and the object's acceleration using Newton's laws. Suitable for high school students in Grades 9-12.

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