A photon of light energy is equal to 

(6.626 × 10−34J.s)(νlight)
 

(6.626 × 10−34J.s)
  (frequency of the light)

hνlight
 

Planck's constant multiplied by the frequency of the light

All of the above are correct

All of the provided options describe the same fundamental equation for the energy of a photon, which is given by:

\[ E = h \nu \]

Where:
- \( E \) is the energy of the photon,
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{J·s} \)),
- \( \nu \) (or "nu") is the frequency of the light.

This equation shows that the energy of a photon is directly proportional to the frequency of the light, and all the given descriptions correctly express this relationship. Therefore, **"All of the above are correct"** is the right answer.

Would you like more details on photon energy or any related topics?

Here are 5 related questions:
1. How does the wavelength of light relate to its frequency and energy?
2. Can photon energy change, and if so, how?
3. How does Planck's constant relate to quantum theory?
4. What role does photon energy play in the photoelectric effect?
5. How does the speed of light affect the energy of a photon?

**Tip:** The higher the frequency of light, the higher the energy of its photons, which is why ultraviolet light has more energy than visible light.

A photon of light energy is equal to (6.626 × 10−34J.s)(νlight) (6.626 × 10−34J.s) (frequency of the light) hνlight Planck's constant multiplied by the frequency of the light All of the above are correct.

Explore the fundamental equation for calculating the energy of a photon using Planck's constant and the frequency of light. This concept is key to understanding photon energy, quantum mechanics, and the relationship between frequency and energy. Suitable for college-level physics students.

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