Math Problem Statement

A photon of light energy is equal to

(6.626 × 10−34J.s)(νlight)

(6.626 × 10−34J.s) (frequency of the light)

hνlight

Planck's constant multiplied by the frequency of the light

All of the above are correct

Solution

All of the provided options describe the same fundamental equation for the energy of a photon, which is given by:

E=hνE = h \nu

Where:

  • EE is the energy of the photon,
  • hh is Planck's constant (6.626×1034J\cdotps6.626 \times 10^{-34} \, \text{J·s}),
  • ν\nu (or "nu") is the frequency of the light.

This equation shows that the energy of a photon is directly proportional to the frequency of the light, and all the given descriptions correctly express this relationship. Therefore, "All of the above are correct" is the right answer.

Would you like more details on photon energy or any related topics?

Here are 5 related questions:

  1. How does the wavelength of light relate to its frequency and energy?
  2. Can photon energy change, and if so, how?
  3. How does Planck's constant relate to quantum theory?
  4. What role does photon energy play in the photoelectric effect?
  5. How does the speed of light affect the energy of a photon?

Tip: The higher the frequency of light, the higher the energy of its photons, which is why ultraviolet light has more energy than visible light.

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Math Problem Analysis

Mathematical Concepts

Quantum Mechanics
Photon Energy
Frequency

Formulas

E = hν (Energy of a photon)

Theorems

Planck's Equation

Suitable Grade Level

College-level Physics