Math Problem Statement
A photon of light energy is equal to
(6.626 × 10−34J.s)(νlight)
(6.626 × 10−34J.s) (frequency of the light)
hνlight
Planck's constant multiplied by the frequency of the light
All of the above are correct
Solution
All of the provided options describe the same fundamental equation for the energy of a photon, which is given by:
Where:
- is the energy of the photon,
- is Planck's constant (),
- (or "nu") is the frequency of the light.
This equation shows that the energy of a photon is directly proportional to the frequency of the light, and all the given descriptions correctly express this relationship. Therefore, "All of the above are correct" is the right answer.
Would you like more details on photon energy or any related topics?
Here are 5 related questions:
- How does the wavelength of light relate to its frequency and energy?
- Can photon energy change, and if so, how?
- How does Planck's constant relate to quantum theory?
- What role does photon energy play in the photoelectric effect?
- How does the speed of light affect the energy of a photon?
Tip: The higher the frequency of light, the higher the energy of its photons, which is why ultraviolet light has more energy than visible light.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Quantum Mechanics
Photon Energy
Frequency
Formulas
E = hν (Energy of a photon)
Theorems
Planck's Equation
Suitable Grade Level
College-level Physics