Math Problem Statement

A pet rescue center is creating a monthly food budget. The center currently has two-thirds as many dogs as cats. Each animal is fed 2 cans of food a day. Dog food costs $0.68 per can, while cat food costs $0.65 per can. The rescue center has budgeted a total of $2581.80 for food for this 30-day month. How many dogs are at the rescue center?

Solution

Let's solve this problem step by step by defining variables and forming equations based on the given information.

Step 1: Define the Variables

Let:

  • CC represent the number of cats.
  • DD represent the number of dogs.

We are told that the rescue center has two-thirds as many dogs as cats. This gives us the relationship: D=23CD = \frac{2}{3}C

Step 2: Calculate the Total Food Costs for the Animals

  • Each dog is fed 2 cans of food per day, and dog food costs $0.68 per can. Therefore, the daily cost for one dog is: 2×0.68=1.36dollars/day.2 \times 0.68 = 1.36 \, \text{dollars/day}. For a 30-day month, the total food cost per dog is: 30×1.36=40.8dollars/month.30 \times 1.36 = 40.8 \, \text{dollars/month}.

  • Each cat is also fed 2 cans of food per day, and cat food costs $0.65 per can. Therefore, the daily cost for one cat is: 2×0.65=1.30dollars/day.2 \times 0.65 = 1.30 \, \text{dollars/day}. For a 30-day month, the total food cost per cat is: 30×1.30=39.0dollars/month.30 \times 1.30 = 39.0 \, \text{dollars/month}.

Step 3: Write the Total Budget Equation

The total food budget is $2581.80 for the month. The total cost for all the dogs and cats must add up to this amount. Therefore, the equation for the total cost becomes: 40.8D+39.0C=2581.8040.8D + 39.0C = 2581.80

Step 4: Substitute D=23CD = \frac{2}{3}C into the Budget Equation

Now substitute D=23CD = \frac{2}{3}C into the equation: 40.8×23C+39.0C=2581.8040.8 \times \frac{2}{3}C + 39.0C = 2581.80 Simplify: 27.2C+39.0C=2581.8027.2C + 39.0C = 2581.80 66.2C=2581.8066.2C = 2581.80

Step 5: Solve for CC

Solve for CC (the number of cats): C=2581.8066.239C = \frac{2581.80}{66.2} \approx 39

Step 6: Solve for DD

Now that we know C=39C = 39, use the relationship D=23CD = \frac{2}{3}C to find the number of dogs: D=23×39=26D = \frac{2}{3} \times 39 = 26

Final Answer:

There are 26 dogs at the rescue center.


Would you like any additional details or have any questions?

Here are five related questions:

  1. How would the budget change if the cost of cat food increased by $0.05 per can?
  2. What if the number of dogs was one-half of the number of cats instead?
  3. How would the monthly food cost change if each animal ate 3 cans per day instead of 2?
  4. What is the cost per animal per day based on this budget?
  5. If the budget increased by 10%, how many more dogs or cats could the center feed?

Tip: When solving word problems, define variables and set up equations based on relationships described in the problem.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Proportions

Formulas

D = (2/3)C
40.8D + 39.0C = 2581.80
C = 2581.80 / 66.2

Theorems

Linear equation solving

Suitable Grade Level

Grades 8-10