Math Problem Statement

Which point could be on the line that is perpendicular to line MN and passes through point K?

Solution

Let's solve the problem based on the information in the image.

Step 1: Find the slope of line MN\overline{MN}

To find the slope of line MN\overline{MN}, we can use the coordinates of points MM and NN.

  • Coordinates of MM (from the graph): M(2,4)M(2, 4)
  • Coordinates of NN (from the graph): N(3,2)N(-3, 2)

The formula for the slope between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is:

slope of MN=y2y1x2x1=422(3)=25\text{slope of } \overline{MN} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{4 - 2}{2 - (-3)} = \frac{2}{5}

Step 2: Find the slope of the line perpendicular to MN\overline{MN}

The slope of the line perpendicular to MN\overline{MN} is the negative reciprocal of 25\frac{2}{5}. So:

slope of perpendicular line=52\text{slope of perpendicular line} = -\frac{5}{2}

Step 3: Equation of the line passing through point K(0,4)K(0, -4)

Now, we need to find the equation of the line that is perpendicular to MN\overline{MN} and passes through point K(0,4)K(0, -4). The point-slope form of the equation of a line is:

yy1=m(xx1)y - y_1 = m(x - x_1)

Substituting m=52m = -\frac{5}{2}, and K(0,4)K(0, -4):

y(4)=52(x0)y - (-4) = -\frac{5}{2}(x - 0)

Simplifying:

y+4=52xy + 4 = -\frac{5}{2}x

y=52x4y = -\frac{5}{2}x - 4

Step 4: Check which point lies on this line

We now check the given options by substituting the coordinates into the equation y=52x4y = -\frac{5}{2}x - 4.

  1. For (0,12)(0, -12): y=52(0)4=4(not 12)y = -\frac{5}{2}(0) - 4 = -4 \quad (\text{not } -12)

  2. For (2,2)(2, 2): y=52(2)4=54=9(not 2)y = -\frac{5}{2}(2) - 4 = -5 - 4 = -9 \quad (\text{not } 2)

  3. For (4,8)(4, 8): y=52(4)4=104=14(not 8)y = -\frac{5}{2}(4) - 4 = -10 - 4 = -14 \quad (\text{not } 8)

  4. For (5,13)(5, 13): y=52(5)4=2524=25282=332=16.5(not 13)y = -\frac{5}{2}(5) - 4 = -\frac{25}{2} - 4 = -\frac{25}{2} - \frac{8}{2} = -\frac{33}{2} = -16.5 \quad (\text{not } 13)

None of these points satisfy the equation, but this is an issue with matching the graph correctly based on how numbers fit. So I

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Slopes of Lines
Perpendicular Lines

Formulas

Slope formula: (y2 - y1) / (x2 - x1)
Equation of a line in point-slope form: y - y1 = m(x - x1)
Negative reciprocal of slope for perpendicular lines

Theorems

Slope-Intercept Theorem
Point-Slope Form of a Line

Suitable Grade Level

Grades 8-10