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The problem asks how many ways a president, vice-president, secretary, and treasurer can be chosen from a committee of 8 people. 

This is a permutation problem because the order in which the positions are filled matters (i.e., the person selected for president is different from the one selected for vice-president, and so on).

To solve, we calculate the number of ways to assign these 4 positions from 8 people:

\[
P(8, 4) = 8 \times 7 \times 6 \times 5 = 1680
\]

Thus, the number of ways to choose a president, vice-president, secretary, and treasurer is **1680**.

Do you want more details or have any questions about this solution?

Here are 5 related questions for deeper understanding:
1. How would the solution change if only 3 positions were chosen instead of 4?
2. What if the positions were indistinguishable? How would that affect the calculation?
3. Can you explain the difference between a permutation and a combination in this context?
4. What happens to the number of ways if we increase the committee size to 10 people?
5. How do you calculate the number of ways if repetitions were allowed?

**Tip:** In permutation problems, always pay attention to whether the order of selection matters—if it does, it's a permutation!

How many ways can a president, vice-president, secretary, and treasurer be chosen from a committee of 8 people?

Learn how to calculate the number of ways to choose a president, vice-president, secretary, and treasurer from a committee of 8 people using permutations. Understand the formula P(8, 4) and the importance of order in combinatorial problems. Suitable for high school students in Grades 9-12.

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