The image contains three mathematical problems related to perimeters and distances. Here's a detailed explanation for each:

Q4:

Problem: A farmer has a rectangular field of length 240 m and breadth 180 m. He wants to fence it with 3 rounds of rope. What is the total length of rope he must buy?

Solution:

1. Length of field: $240 \, \text{m}$
2. Breadth of field: $180 \, \text{m}$
3. Perimeter of field: $2 \times (\text{Length} + \text{Breadth}) = 2 \times (240 + 180) = 2 \times 420 = 840 \, \text{m}$
4. For 3 rounds: $3 \times 840 = 2520 \, \text{m}$

Answer: $2520 \, \text{m}$

Q5:

Problem: Find the cost of fencing a rectangular park of length 250 m and breadth 175 m at the rate of ₹12 per meter.

Solution:

1. Length of park: $250 \, \text{m}$
2. Breadth of park: $175 \, \text{m}$
3. Perimeter of park: $2 \times (\text{Length} + \text{Breadth}) = 2 \times (250 + 175) = 2 \times 425 = 850 \, \text{m}$
4. Cost of fencing: $\text{Perimeter} \times \text{Rate per meter} = 850 \times 12 = ₹10200$

Answer: ₹10200

Q6:

Problem: Find the distance traveled by Shaim if she takes three rounds of a square park of side 70 m.

Solution:

1. Side of square park: $70 \, \text{m}$
2. Perimeter of square park: $4 \times \text{Side} = 4 \times 70 = 280 \, \text{m}$
3. Distance for 3 rounds: $3 \times 280 = 840 \, \text{m}$

Answer: $840 \, \text{m}$

Would you like further clarifications on these problems? Here are some related questions:

1. How is the perimeter formula for a rectangle derived?
2. Why is the total rope required multiplied by 3 in Q4?
3. What is the difference between area and perimeter?
4. How would the cost change in Q5 if the rate per meter increased to ₹15?
5. What would the total distance be in Q6 if Shaim took 5 rounds?

Tip: Always verify units and double-check calculations for accuracy.