To find the perimeter of the composite figure, we need to calculate the sum of all the outer sides.

1. Square:

   • Each side of the square is $5 \, \text{cm}$, so the perimeter of the square alone would be $4 \times 5 = 20 \, \text{cm}$, but we need to be careful to avoid double-counting shared sides with the triangle.

2. Triangle:

   • The triangle is adjacent to the square, and its base is also $5 \, \text{cm}$, which is the same as one side of the square. Since they are adjacent, this side is shared and should not be counted twice.
   • The other two sides of the triangle are each $6 \, \text{cm}$, so their total length is $6 + 6 = 12 \, \text{cm}$.

Now, let's combine everything:

• The perimeter of the square includes 3 unshared sides: $5 + 5 + 5 = 15 \, \text{cm}$.
• The two remaining sides of the triangle contribute $6 + 6 = 12 \, \text{cm}$.

So, the total perimeter of the composite figure is: $15 \, \text{cm} + 12 \, \text{cm} = 27 \, \text{cm}$

Thus, the perimeter of the composite figure is $27 \, \text{cm}$.

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Would you like further details or have any questions?

Here are some related questions:

1. What is the area of the composite figure?
2. How would the perimeter change if the triangle's sides were different lengths?
3. How can we find the length of a diagonal of the square?
4. What would happen to the perimeter if the side of the square were doubled?
5. How does the perimeter change if a different polygon, like a pentagon, is adjacent to the square instead of a triangle?

Tip: Always ensure that shared sides in composite figures are not counted twice when calculating perimeter!