https://file.aiquickdraw.com/mathbot/file/1727318189100bnbhoae1.jpg

The problem describes a swimming pool drawing with dimensions of 5 inches and 2 inches, with a scale of **1 inch = 15 feet** in real life. We are asked to find the perimeter of the actual swimming pool.

### Step-by-Step Solution:

1. **Scale Conversion:**
   - The dimensions in the drawing are 5 inches and 2 inches.
   - Using the scale 1 inch = 15 feet, the actual dimensions of the swimming pool will be:
     - Length: \( 5 \, \text{inches} \times 15 = 75 \, \text{feet} \)
     - Width: \( 2 \, \text{inches} \times 15 = 30 \, \text{feet} \)

2. **Perimeter of a Rectangle Formula:**
   The perimeter \( P \) of a rectangle is given by:
   \[
   P = 2 \times (\text{Length} + \text{Width})
   \]

3. **Calculate the Perimeter:**
   Using the actual dimensions:
   \[
   P = 2 \times (75 \, \text{feet} + 30 \, \text{feet}) = 2 \times 105 = 210 \, \text{feet}
   \]

Thus, the perimeter of the actual rectangular swimming pool is **210 feet**.

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Would you like further details or have any questions? Here are some related problems to expand on this:

1. What would the area of the swimming pool be in square feet?
2. How would the perimeter change if the scale was 1 inch = 10 feet?
3. What would be the dimensions in real life if the drawing was enlarged to 10 inches by 4 inches?
4. How do we calculate the diagonal length of the swimming pool?
5. Can we determine the swimming pool's perimeter if the shape were irregular?

**Tip:** Always double-check that the correct units (feet, inches, etc.) are used when performing calculations with scale models.

The drawing represents a swimming pool in real life. If the scale is 1 inch = 15 feet, what is the perimeter of the actual rectangular swimming pool?

Solve a geometry problem involving the calculation of the perimeter of a rectangular swimming pool. The problem uses a 1 inch = 15 feet scale and covers the concept of scaling and perimeter calculation. Suitable for students in Grades 5-7.

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