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The question asks to find the partial products for \( 16 \times 24 \) by selecting all that apply from the given choices.

To compute \( 16 \times 24 \) using partial products, we can break the numbers into smaller parts. Let's break it down step by step:

### Break 16 and 24 into parts:
- \( 16 = 10 + 6 \)
- \( 24 = 20 + 4 \)

Now, apply the distributive property to calculate the partial products:

\[
16 \times 24 = (10 + 6) \times (20 + 4)
\]

This expands to:

\[
= 10 \times 20 + 10 \times 4 + 6 \times 20 + 6 \times 4
\]

### Calculate each partial product:
1. \( 10 \times 20 = 200 \)
2. \( 10 \times 4 = 40 \)
3. \( 6 \times 20 = 120 \)
4. \( 6 \times 4 = 24 \)

So, the partial products are \( 200 \), \( 40 \), \( 120 \), and \( 24 \).

### Correct choices:
- Option **B**: \( 200; 120; 40; 24 \)
- Option **C**: \( 24; 120; 40; 200 \)

Both these options contain the correct partial products.

Would you like more details on how these calculations work? 

### Related questions:
1. How can the distributive property help in breaking down multiplication problems?
2. What are some other strategies for calculating partial products?
3. How does breaking numbers down into parts simplify multiplication?
4. What would be the partial products for \( 15 \times 27 \)?
5. How do partial products help in understanding larger multiplication?

### Tip:
Breaking down numbers into smaller components can make large multiplication problems much easier to solve. This method is particularly useful for mental math.

Select all of the partial products that would be used to find 16 × 24. Options: A. 200; 12; 4; 24, B. 200; 120; 40; 24, C. 24; 120; 40; 200, D. 42; 40; 12; 2,000, E. 2,000; 1,200; 40; 24

Learn how to calculate the partial products for the multiplication problem 16 × 24. This problem demonstrates the use of the distributive property to break numbers into parts and simplify large multiplication. Suitable for students in Grades 4-6.

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