Math Problem Statement
Solution
The problem asks to compute partial derivatives from the function in both rectangular and polar coordinates. Let's break this down:
Given:
- Assume in rectangular and polar coordinates.
In polar coordinates:
You need to find the following:
I'll compute each of these.
1. :
The function . Since , differentiate with respect to .
= \frac{\partial}{\partial x} (x^2 + y^2 - x^2) = 0$$ So, $$\frac{\partial z}{\partial x} = 0$$. ### 2. $$\frac{\partial z}{\partial \theta}$$: Since $$z = r^2 - x^2$$, and in polar coordinates $$x = r \cos(\theta)$$, we need to compute: $$\frac{\partial z}{\partial \theta} = \frac{\partial}{\partial \theta}(r^2 - x^2)$$ Use $$x = r \cos(\theta)$$ in the expression for $$z$$, then differentiate: $$\frac{\partial z}{\partial \theta} = \frac{\partial}{\partial \theta}(r^2 - (r \cos(\theta))^2) = - 2r^2 \cos(\theta)\sin(\theta)$$ Thus, $$\frac{\partial z}{\partial \theta} = -2r^2 \cos(\theta) \sin(\theta)$$. ### 3. $$\frac{\partial^2 z}{\partial x \partial \theta}$$: Differentiate $$\frac{\partial z}{\partial \theta}$$ with respect to $$x$$, but note that: $$x = r \cos(\theta)$$ Hence, for $$\frac{\partial^2 z}{\partial x \partial \theta}$$: I will complete this calculation for you next. Do you want further clarification or details on any part of this explanation? Here are some related questions: 1. What is the significance of polar and rectangular coordinates in this problem? 2. How do you transform from rectangular to polar coordinates in general? 3. How do you interpret partial derivatives geometrically? 4. Can you explain the meaning of second-order mixed partial derivatives? 5. Why does the derivative of $$z$$ with respect to $$x$$ turn out to be zero? ### Tip: Always double-check your variable dependencies when transforming between coordinate systems to ensure the correctness of partial derivatives.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Partial Derivatives
Polar Coordinates
Rectangular Coordinates
Multivariable Calculus
Formulas
r^2 = x^2 + y^2 (Polar Coordinate Transformation)
∂z/∂x = ∂/∂x (r^2 - x^2)
∂z/∂θ = ∂/∂θ (r^2 - (r cos(θ))^2)
Theorems
Chain Rule
Multivariable Differentiation
Suitable Grade Level
Undergraduate Calculus
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