Math Problem Statement

and it doesn't matter is a multivariable function? what if i derived with respect to theta? why is the right choice to derive with respect to r?

Solution

The function you're referring to sounds like it is expressed in polar coordinates, which suggests it might be a multivariable function of two variables: rr (radius) and θ\theta (angle).

In polar coordinates, a function typically depends on rr and θ\theta as follows:

f(r,θ)f(r, \theta)

Partial Derivatives in Polar Coordinates

If you differentiate a function with respect to rr, you're measuring how the function changes as you move radially outward or inward from the origin (changing distance from the center).

If you differentiate with respect to θ\theta, you're measuring how the function changes as you rotate around the origin (changing the angle).

Why Deriving with Respect to rr Might Be the "Right" Choice

In many physical and geometric contexts, radial changes are often more important or more intuitive to study. For example:

  1. Radial Symmetry: In cases where the function or system is radially symmetric, changes with respect to rr can capture the primary variations in the function, while θ\theta may have little to no influence.

  2. Distance from Origin: Many functions in polar coordinates are naturally more dependent on the distance from the origin (i.e., rr). For example, functions describing gravitational potential or electric fields depend primarily on the radial distance.

Why θ\theta Might Be Less Significant in Some Cases

For certain problems, changes with respect to θ\theta might not significantly affect the outcome if the function is symmetric or if the focus is on radial distances. In such cases, the behavior of the function in the radial direction (i.e., how it changes with rr) can provide the most insightful information.

General Derivative Rules

For a function f(r,θ)f(r, \theta), you can compute the partial derivatives with respect to both rr and θ\theta:

  • Partial derivative with respect to rr: fr\frac{\partial f}{\partial r}

  • Partial derivative with respect to θ\theta: fθ\frac{\partial f}{\partial \theta}

If the problem involves radial motion, it's common to take the derivative with respect to rr, as that may capture the most critical changes.

Would you like to see an example or explanation involving a specific function or scenario?

5 Related Questions:

  1. How do polar coordinates differ from Cartesian coordinates when taking derivatives?
  2. What is the relationship between Cartesian and polar derivatives?
  3. In which contexts do we commonly use polar coordinates to express multivariable functions?
  4. How can we convert a function from polar coordinates to Cartesian coordinates for differentiation?
  5. What types of symmetry in a function might influence your choice of which variable to derive with respect to?

Tip:

In polar coordinates, visualizing the problem geometrically (e.g., in terms of radial distance and angle) can help decide which variable to differentiate with respect to.

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Math Problem Analysis

Mathematical Concepts

Multivariable Calculus
Polar Coordinates
Partial Derivatives

Formulas

f(r, θ)
∂f/∂r (Partial derivative with respect to r)
∂f/∂θ (Partial derivative with respect to θ)

Theorems

Fundamentals of Partial Derivatives
Polar Coordinate System

Suitable Grade Level

Undergraduate Calculus