Math Problem Statement

Find the partial derivatives indicated. Assume the variables are restricted to a domain on which the function is defined. Given \( f(x, y) = x^2 + 4x^3y \), find \( f_x(1, 4) \) and \( f_y(1, 4) \).

Solution

To solve this problem, let's calculate the partial derivatives of the function f(x,y)=x2+4x3yf(x, y) = x^2 + 4x^3y with respect to xx and yy, and then evaluate them at the point (1,4)(1, 4).

Step 1: Find fx(x,y)f_x(x, y)

The partial derivative of ff with respect to xx is: fx(x,y)=x(x2+4x3y)f_x(x, y) = \frac{\partial}{\partial x}(x^2 + 4x^3y) Differentiating term-by-term:

  1. x(x2)=2x\frac{\partial}{\partial x}(x^2) = 2x
  2. x(4x3y)=12x2y\frac{\partial}{\partial x}(4x^3y) = 12x^2y (since yy is treated as a constant)

So, fx(x,y)=2x+12x2yf_x(x, y) = 2x + 12x^2y

Step 2: Evaluate fx(1,4)f_x(1, 4)

Substitute x=1x = 1 and y=4y = 4 into fx(x,y)f_x(x, y): fx(1,4)=2(1)+12(1)2(4)=2+48=50f_x(1, 4) = 2(1) + 12(1)^2(4) = 2 + 48 = 50

Step 3: Find fy(x,y)f_y(x, y)

The partial derivative of ff with respect to yy is: fy(x,y)=y(x2+4x3y)f_y(x, y) = \frac{\partial}{\partial y}(x^2 + 4x^3y) Differentiating term-by-term:

  1. y(x2)=0\frac{\partial}{\partial y}(x^2) = 0 (since x2x^2 is independent of yy)
  2. y(4x3y)=4x3\frac{\partial}{\partial y}(4x^3y) = 4x^3

So, fy(x,y)=4x3f_y(x, y) = 4x^3

Step 4: Evaluate fy(1,4)f_y(1, 4)

Substitute x=1x = 1 into fy(x,y)f_y(x, y): fy(1,4)=4(1)3=4f_y(1, 4) = 4(1)^3 = 4

Final Answers

fx(1,4)=50f_x(1, 4) = 50 fy(1,4)=4f_y(1, 4) = 4

Would you like a deeper explanation of any steps?


Here are some related questions:

  1. What is the interpretation of partial derivatives in a real-world context?
  2. How does the chain rule apply when differentiating functions of multiple variables?
  3. What is the geometric meaning of fxf_x and fyf_y at a point on a surface?
  4. How would the second partial derivatives of this function be calculated?
  5. What happens to fxf_x and fyf_y if yy is treated as a function of xx?

Tip: Remember that when finding partial derivatives, treat all other variables as constants with respect to the variable of differentiation.

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Math Problem Analysis

Mathematical Concepts

Calculus
Partial Derivatives
Multivariable Functions

Formulas

f_x(x, y) = \frac{\partial}{\partial x}(x^2 + 4x^3y)
f_y(x, y) = \frac{\partial}{\partial y}(x^2 + 4x^3y)

Theorems

Partial Derivative Rules
Power Rule for Differentiation

Suitable Grade Level

College Level (Calculus I or II)