Math Problem Statement
Given the function f (y, z) = (sin y)ez3−z−1
- eyz (a) Determine fz (b) Determine fy (c) Determine fyz
Solution
Given the function , we will compute each of the partial derivatives step by step.
(a) Determine (the partial derivative with respect to ):
We apply the rules of differentiation, treating as a constant.
First term:
The derivative of with respect to is:
Thus, the derivative of the first term is:
Second term:
The derivative of with respect to is:
So the partial derivative is:
(b) Determine (the partial derivative with respect to ):
We now differentiate with respect to , treating as constant.
First term:
The derivative of is . So, the derivative of the first term is:
Second term:
The derivative of with respect to is:
So the partial derivative is:
(c) Determine (the mixed partial derivative with respect to and ):
Now, we differentiate with respect to .
From part (b), we know that:
First term:
The derivative with respect to is:
Second term:
The derivative with respect to is:
So the mixed partial derivative is:
Summary of Results:
(a)
(b)
(c)
Would you like more details or have any questions?
Here are 5 related questions to expand on this topic:
- What is the second partial derivative of the function?
- How does the chain rule apply when computing partial derivatives?
- Can you find the critical points of the function ?
- How would the function change if the exponent in were ?
- What happens if or ? How does this simplify ?
Tip: When differentiating exponentials with a variable in the exponent, remember to apply the chain rule carefully!
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Math Problem Analysis
Mathematical Concepts
Partial Derivatives
Multivariable Calculus
Exponentiation
Trigonometric Functions
Formulas
f_z = (\sin y) e^{z^3 - z - 1} (3z^2 - 1) + y e^{yz}
f_y = (\cos y) e^{z^3 - z - 1} + z e^{yz}
f_{yz} = (\cos y) e^{z^3 - z - 1} (3z^2 - 1) + e^{yz} + z y e^{yz}
Theorems
Chain Rule
Product Rule
Suitable Grade Level
College Level (Calculus II or Multivariable Calculus)
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