Math Problem Statement

Find derivative of this,: e^(x^2+y^2)

Solution

To find the derivative of the function ex2+y2e^{x^2 + y^2} with respect to xx, we'll need to apply the chain rule.

Given: f(x,y)=ex2+y2f(x, y) = e^{x^2 + y^2}

We are finding the partial derivative with respect to xx, assuming yy is a constant.

Step-by-step solution:

  1. Differentiate the exponential function: xex2+y2=ex2+y2x(x2+y2)\frac{\partial}{\partial x} e^{x^2 + y^2} = e^{x^2 + y^2} \cdot \frac{\partial}{\partial x}(x^2 + y^2)

  2. Differentiate x2+y2x^2 + y^2 with respect to xx: x(x2+y2)=2x\frac{\partial}{\partial x}(x^2 + y^2) = 2x (Since the derivative of y2y^2 with respect to xx is 0, because yy is constant.)

  3. Combine the results: xex2+y2=ex2+y22x\frac{\partial}{\partial x} e^{x^2 + y^2} = e^{x^2 + y^2} \cdot 2x

Thus, the derivative of ex2+y2e^{x^2 + y^2} with respect to xx is: xex2+y2=2xex2+y2\frac{\partial}{\partial x} e^{x^2 + y^2} = 2x e^{x^2 + y^2}

Would you like further details or clarification?

Here are 5 related questions to deepen your understanding:

  1. What is the derivative of ex2y2e^{x^2 - y^2} with respect to xx?
  2. How would you find the derivative of ex2+y2e^{x^2 + y^2} with respect to yy?
  3. Can you find the second derivative of ex2+y2e^{x^2 + y^2} with respect to xx?
  4. What is the total differential of ex2+y2e^{x^2 + y^2}?
  5. How would you approach finding the gradient of ex2+y2e^{x^2 + y^2}?

Tip: When differentiating exponential functions, always remember to apply the chain rule, especially when the exponent is a function of multiple variables.

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Math Problem Analysis

Mathematical Concepts

Calculus
Partial Derivatives
Exponential Functions

Formulas

Chain Rule for Derivatives: d/dx [f(g(x))] = f'(g(x)) * g'(x)
Partial Derivative of e^(x^2 + y^2) with respect to x: ∂/∂x e^(x^2 + y^2) = e^(x^2 + y^2) * ∂/∂x (x^2 + y^2)

Theorems

Chain Rule

Suitable Grade Level

Undergraduate Calculus