Math Problem Statement
Solution
To solve the problem, we will follow these steps:
1. Parametric Equation of a Circle (Center at the Origin):
For a circle with radius and center at the origin , the parametric equations are: where is the parameter (the angle), and it ranges from to .
2. Finding the Slopes at Specific Angles (0°, 45°, and 90°):
The slope of the tangent line to the circle at any point can be found by differentiating the parametric equations with respect to the angle .
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Step 1: Parametric derivatives Differentiate and with respect to :
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Step 2: Tangent slope formula The slope of the tangent to the circle is given by:
3. Slopes at Specific Angles:
- At :
- At :
- At :
Summary of Results:
- The parametric equations for the circle centered at the origin are:
- The slopes of the tangent at the angles , , and are:
Would you like further clarification on any of the steps?
Here are some related questions to explore:
- What happens to the parametric equations if the circle is shifted from the origin?
- How would you compute the tangent slope at other angles, like 30° or 60°?
- Can you develop parametric equations for ellipses or other conic sections?
- How would the parametric equations change for a circle with a different radius?
- How can the parametric equation be extended to 3D, such as for a sphere?
Tip: Parametric equations can be very useful for describing curves and geometric shapes beyond circles—try applying them to ellipses or spirals!
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Math Problem Analysis
Mathematical Concepts
Trigonometry
Calculus
Geometry
Formulas
x = r cos(θ)
y = r sin(θ)
Slope of the tangent = -cot(θ)
Theorems
Parametric equations for a circle
Tangent slope formula
Suitable Grade Level
Grades 11-12
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