Math Problem Statement

Develop a parametric equation of a circle in which the center lies on origin. Also determine the slopes at angle 0, 45, and 90 degrees.

Solution

To solve the problem, we will follow these steps:

1. Parametric Equation of a Circle (Center at the Origin):

For a circle with radius rr and center at the origin (0,0)(0,0), the parametric equations are: x=rcosθx = r \cos \theta y=rsinθy = r \sin \theta where θ\theta is the parameter (the angle), and it ranges from 00 to 2π2\pi.

2. Finding the Slopes at Specific Angles (0°, 45°, and 90°):

The slope of the tangent line to the circle at any point can be found by differentiating the parametric equations with respect to the angle θ\theta.

  • Step 1: Parametric derivatives Differentiate x=rcosθx = r \cos \theta and y=rsinθy = r \sin \theta with respect to θ\theta: dxdθ=rsinθ\frac{dx}{d\theta} = -r \sin \theta dydθ=rcosθ\frac{dy}{d\theta} = r \cos \theta

  • Step 2: Tangent slope formula The slope of the tangent to the circle is given by: slope=dy/dθdx/dθ=rcosθrsinθ=cotθ\text{slope} = \frac{dy/d\theta}{dx/d\theta} = \frac{r \cos \theta}{-r \sin \theta} = -\cot \theta

3. Slopes at Specific Angles:

  • At θ=0\theta = 0^\circ: slope=cot(0)=0\text{slope} = -\cot(0^\circ) = 0
  • At θ=45\theta = 45^\circ: slope=cot(45)=1\text{slope} = -\cot(45^\circ) = -1
  • At θ=90\theta = 90^\circ: slope=cot(90)=0\text{slope} = -\cot(90^\circ) = 0

Summary of Results:

  • The parametric equations for the circle centered at the origin are: x=rcosθ,y=rsinθx = r \cos \theta, \quad y = r \sin \theta
  • The slopes of the tangent at the angles 00^\circ, 4545^\circ, and 9090^\circ are: Slope at 0=0,Slope at 45=1,Slope at 90=0\text{Slope at } 0^\circ = 0, \quad \text{Slope at } 45^\circ = -1, \quad \text{Slope at } 90^\circ = 0

Would you like further clarification on any of the steps?

Here are some related questions to explore:

  1. What happens to the parametric equations if the circle is shifted from the origin?
  2. How would you compute the tangent slope at other angles, like 30° or 60°?
  3. Can you develop parametric equations for ellipses or other conic sections?
  4. How would the parametric equations change for a circle with a different radius?
  5. How can the parametric equation be extended to 3D, such as for a sphere?

Tip: Parametric equations can be very useful for describing curves and geometric shapes beyond circles—try applying them to ellipses or spirals!

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Calculus
Geometry

Formulas

x = r cos(θ)
y = r sin(θ)
Slope of the tangent = -cot(θ)

Theorems

Parametric equations for a circle
Tangent slope formula

Suitable Grade Level

Grades 11-12