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The given equation of Line 2 is \( x = -12 \), which is a vertical line. Here are the steps to find the required equations:

### 1. **Equation of the line parallel to Line 2**:
- A line parallel to a vertical line also has the same form, i.e., \( x = \text{constant} \).
- Since the parallel line must pass through the point \( (2, -5) \), the equation of the line is:
\[
x = 2
\]
This is because the \(x\)-coordinate is constant for vertical lines.

### 2. **Equation of the line perpendicular to Line 2**:
- A line perpendicular to a vertical line is a horizontal line, which has the form \( y = \text{constant} \).
- Since the perpendicular line must pass through \( (2, -5) \), the equation of this line is:
\[
y = -5
\]
This is because the \(y\)-coordinate is constant for horizontal lines.

### Final Answers:
- Equation of the line parallel to Line 2: \( x = 2 \)
- Equation of the line perpendicular to Line 2: \( y = -5 \)

Would you like more details or further explanation on this? Here are some related questions to think about:

1. What is the general form of the equation of a vertical line?
2. How can you determine the slope of a vertical or horizontal line?
3. Why do parallel lines have the same equation form when they are vertical?
4. What is the slope of a line perpendicular to a vertical line?
5. How would you write the equation of a non-vertical, non-horizontal line passing through two points?

**Tip:** Remember that vertical lines have undefined slopes, while horizontal lines have a slope of 0.

Consider Line 2, which has the equation: x = -12. Give the equation of the line parallel to Line 2 which passes through (2, -5). Give the equation of the line perpendicular to Line 2 which passes through (2, -5).

Learn how to find the equations of lines parallel and perpendicular to a vertical line. This problem focuses on Line 2, which is x = -12, and requires finding lines passing through the point (2, -5). Suitable for students in Grades 8-10.

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