Math Problem Statement

Given m || n, find the value of x with the angles (4x + 8)° and (4x - 20)° formed by a transversal.

Solution

The problem shows two parallel lines, mnm \parallel n, with a transversal intersecting them. The given angles at the intersections are (4x+8)(4x + 8)^\circ and (4x20)(4x - 20)^\circ.

Because the lines mm and nn are parallel and the transversal creates corresponding angles, these angles are congruent (equal).

Thus, we can set the two angle expressions equal to each other:

4x+8=4x204x + 8 = 4x - 20

Now let's solve for xx.

  1. Subtract 4x4x from both sides: 8=208 = -20 This gives a contradiction, which means that the angles might not be corresponding but rather supplementary (since their sum must equal 180180^\circ).

Thus, the correct relation should be:

(4x+8)+(4x20)=180(4x + 8) + (4x - 20) = 180

Now let's solve this equation:

4x+8+4x20=1804x + 8 + 4x - 20 = 180 8x12=1808x - 12 = 180 8x=1928x = 192 x=1928=24x = \frac{192}{8} = 24

Thus, the value of xx is 2424.

Would you like more details on any of the steps? Here are five related questions to deepen understanding:

  1. What are corresponding angles in parallel line geometry?
  2. How can we identify supplementary angles in different transversal cases?
  3. How can we confirm whether angles should be set equal or supplementary?
  4. What would happen if the transversal intersected non-parallel lines?
  5. How can parallel line properties help solve problems with more complex angles?

Tip: Always check whether the angles formed by a transversal on parallel lines are corresponding, alternate, or supplementary, as this guides the correct equation to solve.

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Math Problem Analysis

Mathematical Concepts

Parallel Lines
Transversals
Angle Properties

Formulas

(4x + 8) + (4x - 20) = 180

Theorems

Supplementary Angles Theorem
Angle Relationships in Parallel Lines

Suitable Grade Level

Grades 8-10