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The given image shows a current source of 5 A splitting into two parallel resistors, one with a resistance of \(5 \, \Omega\) and the other with \(36 \, \Omega\). We are tasked with finding the current \(I_2\) through the \(36 \, \Omega\) resistor.

### Steps to solve the problem:
1. The total current from the current source is 5 A, which is split between two resistors in parallel.
2. Using Ohm's Law \( V = IR \), the voltage across both resistors is the same, as they are in parallel.

Let \( V_1 \) and \( V_2 \) represent the voltage across the \(5 \, \Omega\) and \(36 \, \Omega\) resistors, respectively. Since they are in parallel:
\[ V_1 = V_2 \]

Using Ohm's law for each resistor:
\[
V_1 = I_1 \cdot 5 \, \Omega
\]
\[
V_2 = I_2 \cdot 36 \, \Omega
\]
Since \( V_1 = V_2 \), we have:
\[
I_1 \cdot 5 = I_2 \cdot 36
\]
This simplifies to:
\[
I_1 = \frac{36}{5} \cdot I_2
\]

Now, applying Kirchhoff's Current Law (KCL) at the node where the current splits:
\[
I_1 + I_2 = 5 \, \text{A}
\]

Substitute \( I_1 = \frac{36}{5} I_2 \) into the equation:
\[
\frac{36}{5} I_2 + I_2 = 5
\]
Simplifying this:
\[
\left( \frac{36}{5} + 1 \right) I_2 = 5
\]
\[
\frac{41}{5} I_2 = 5
\]
\[
I_2 = \frac{5 \cdot 5}{41} = \frac{25}{41} \approx 0.61 \, \text{A}
\]

Thus, the current \(I_2\) is approximately \( 0.61 \, \text{A} \).

### Correct answer: 
**Option c. 0.61 A**

Would you like further details or have any questions? Here are some related questions you can explore:

1. How do we calculate the voltage across a resistor in a parallel circuit?
2. What is Kirchhoff's Current Law and how is it applied in this case?
3. How can we determine the total resistance in a parallel circuit?
4. What happens to the current in each branch if the resistances change?
5. How does Ohm's Law relate voltage, current, and resistance?

**Tip:** In parallel circuits, the voltage across each resistor is always the same, but the current divides according to the resistance of each branch.

What is the current I2 in the given parallel circuit with a 5 A source, 5 Ω, and 36 Ω resistors?

Learn how to calculate the current I2 in a parallel circuit where a 5 A current source splits between a 5 Ω and a 36 Ω resistor using Ohm's Law and Kirchhoff's Current Law. Suitable for students in Grades 10-12.

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