https://file.aiquickdraw.com/mathbot/file/1726546098602eltvpx97.jpg

Let's break down the problem step by step:

The Panthers have 17 wins and 1 loss in the 2015-16 season, so their win-to-loss ratio is:
\[
\frac{17}{1}
\]
This ratio means they win 17 games for every 1 game they lose.

Now, the problem asks how many games they would lose if 90 additional games were played while maintaining the same win-loss ratio.

### Step 1: Find the total number of sets of 18 games (17 wins + 1 loss) they would play.

Each set of games consists of 17 wins and 1 loss, totaling:
\[
17 + 1 = 18 \text{ games per set}
\]
To find how many sets of 18 games fit into 90 games:
\[
\frac{90}{18} = 5 \text{ sets of 18 games}
\]

### Step 2: Determine the total number of losses.

Since they lose 1 game for each set of 18 games, and they will play 5 sets of 18 games:
\[
5 \times 1 = 5 \text{ losses}
\]

### Final Answer:
If the Panthers played 90 additional games, they would lose **5 games**.

Would you like more details or have any questions?

Here are 5 related questions to consider:
1. How many total wins would the Panthers have after playing 90 additional games?
2. What would be the total number of games they played after the additional 90 games?
3. What percentage of the total games would the Panthers have won?
4. How would the answer change if the win-loss ratio were different?
5. What would happen if they lost 2 games instead of 1 in their current ratio?

**Tip**: Ratios are a useful way to maintain relationships between numbers when scaling them up or down.

The Panthers current statistics for wins versus losses in the 2015-16 season is 17 wins and 1 loss. If they were able to maintain this same rate of winning, how many games would the Panthers lose if 90 additional games were played?

Learn how to calculate how many games the Panthers would lose if they played 90 additional games while maintaining a win-loss ratio of 17:1. This problem covers ratio and proportion concepts, suitable for Grades 5-7.

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